OAI/Algebra/Finitistic/Rectification/ColumnComplex.lean

GitHub source file

16 declarations, 0 contain sorry, 0 declared as axioms

  1. instance OAI.ExternalTensor.Section4.rightModuleK line 14
  2. instance OAI.ExternalTensor.Section4.rightModuleTower line 16
  3. abbrev OAI.ExternalTensor.Section4.Enveloping line 22
  4. abbrev OAI.ExternalTensor.Section4.RightComplex line 23
  5. abbrev OAI.ExternalTensor.Section4.BiComplex line 24
  6. def OAI.ExternalTensor.Section4.columnFunctor line 27

    Source documentation

    Induction by the actual left ideal Be, on right modules and maps.

    def columnFunctor (e : B) : ModuleCat.{u} Bᵐᵒᵖ ⥤ ModuleCat.{u} (Enveloping k B) where
    …

    Mentions: OAI.ExternalTensor.Section4.Enveloping

  7. instance OAI.ExternalTensor.Section4.columnFunctor_additive line 34
  8. instance OAI.ExternalTensor.Section4.columnFunctor_linear line 37
  9. abbrev OAI.ExternalTensor.Section4.columnComplex line 47
  10. def OAI.ExternalTensor.Section4.pathNat line 51

    Source documentation

    Right multiplication on the left tensor factor, natural in the right module.

    def pathNat (ei ej a : B) (ha : a * ei = a) :
        columnFunctor k B ej ⟶ columnFunctor k B ei where
    …

    Mentions: OAI.ExternalTensor.Section4.columnFunctor

  11. abbrev OAI.ExternalTensor.Section4.path line 62
  12. theorem OAI.ExternalTensor.Section4.path_naturality line 66
  13. theorem OAI.ExternalTensor.Section4.sum_f line 72
  14. theorem OAI.ExternalTensor.Section4.sum_hom line 76
  15. theorem OAI.ExternalTensor.Section4.sum_smul_component_apply line 81
  16. theorem OAI.ExternalTensor.Section4.paths_relation line 94

    Source documentation

    The vertex-zero component vanishes by the actual quadratic relation in B.

    theorem paths_relation {A J : Type} [Fintype A] [Fintype J]
        (e₀ e₁ e₂ : B) (a : A → B) (b : J → B)
        (ha : ∀ i, a i * e₀ = a i) (hb : ∀ j, b j * e₁ = b j)
        (r : A → J → k) (hr : ∑ i, ∑ j, r i j • (b j * a i) = 0)
        (D : RightComplex B) :
        ∑ i, ∑ j, r i j • (path k B e₁ e₂ (b j) (hb j) D ≫
          path k B e₀ e₁ (a i) (ha i) D) = 0 := by
    …

    Mentions: OAI.ExternalTensor.Section4.RightComplex, OAI.ExternalTensor.Section4.path