FormalConjectures/OEIS/2454.lean
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- L4DEL
- Lean4 Domain Explanation Language
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Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
7 declarations, 1 contain sorry, 0 declared as axioms
Central factorial numbers: $((2n)!!)^2$
Central factorial numbers: $a(n) = 4^n (n!)^2 = ((2n)!!)^2$.
References:
Imports (1)
- def
OeisA2454.aCentral factorial numbers: $a(n) = 4^n (n!)^2$ line 35 sourceSource documentation
Central factorial numbers: $a(n) = 4^n (n!)^2$.
standard axioms: propext what this means
Statement uses:
NatProof uses:
HMul.hMul,HPow.hPow,OfNat.ofNat,Nat.factorial7 instances, coercions and auxiliary constants left out.
def a (n : ℕ) : ℕ := …
- theorem
OeisA2454.a_0Value of the sequenceaat 0 line 40 sourceSource documentation
Value of the sequence
aat 0.standard axioms: propext what this means
Statement uses:
Eq,Nat, OeisA2454.a,OfNat.ofNatProof uses:
Eq.refl2 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem a_0 : a 0 = 1 := by rfl …
Mentions: OeisA2454.a
- theorem
OeisA2454.a_1Value of the sequenceaat 1 line 44 sourceSource documentation
Value of the sequence
aat 1.standard axioms: propext what this means
Statement uses:
Eq,Nat, OeisA2454.a,OfNat.ofNatProof uses:
Eq.refl2 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem a_1 : a 1 = 4 := by rfl …
Mentions: OeisA2454.a
- theorem
OeisA2454.a_2Value of the sequenceaat 2 line 48 sourceSource documentation
Value of the sequence
aat 2.standard axioms: propext what this means
Statement uses:
Eq,Nat, OeisA2454.a,OfNat.ofNatProof uses:
Eq.refl2 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem a_2 : a 2 = 64 := by rfl …
Mentions: OeisA2454.a
- theorem
OeisA2454.a_3Value of the sequenceaat 3 line 52 sourceSource documentation
Value of the sequence
aat 3.standard axioms: propext what this means
Statement uses:
Eq,Nat, OeisA2454.a,OfNat.ofNatProof uses:
Eq.refl2 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem a_3 : a 3 = 2304 := by rfl …
Mentions: OeisA2454.a
- theorem
OeisA2454.a_4Value of the sequenceaat 4 line 56 sourceSource documentation
Value of the sequence
aat 4.standard axioms: propext what this means
Statement uses:
Eq,Nat, OeisA2454.a,OfNat.ofNatProof uses:
Eq.refl2 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem a_4 : a 4 = 147456 := by rfl …
Mentions: OeisA2454.a
- theorem
OeisA2454.conjectureLet $\zeta$ be a primitive $(2n+1)$-th root of unity sorry line 69 sourceSource documentation
Let $\zeta$ be a primitive $(2n+1)$-th root of unity. Then the permanent of the $2n \times 2n$ matrix $[m(j,k)]_{j,k=1..2n}$ is $a(n)/(2n+1) = ((2n)!!)^2/(2n+1)$, where $m(j,k)$ is $1$ or $(1+\zeta^{j-k})/(1-\zeta^{j-k})$ according as $j = k$ or not.
- Zhi-Wei Sun, Jun 26 2022
Proved by [SSX22], Theorem 1.3(ii): for odd $m > 1$ and $\zeta$ a primitive $m$-th root of unity, the permanent of $[c_{j,k}]_{1 \le j,k \le m-1}$ is $((m-1)!!)^2/m$. Take $m = 2n+1$; translating both matrix indices by one leaves $j - k$ unchanged. For $n = 0$ the matrix is empty and both sides are $1$.
depends on sorry what this means
Statement uses:
Nat,HMul.hMul,OfNat.ofNat,HAdd.hAdd,Complex,IsPrimitiveRoot,Eq,Matrix.permanent,Fin,ite,Int,HSub.hSub,HDiv.hDiv,HPow.hPow, OeisA2454.aProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous52 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem conjecture (n : ℕ) : let N : ℕ := 2 * n …