FormalConjectures/ErdosProblems/893.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

3 declarations, 2 contain sorry, 0 declared as axioms

Erdős Problem 893

References:

Imports (1)
  1. def Erdos893.f Definition of function $f(n) := \sum_{1\leq k\leq n}\tau(2^k-1)$ line 39 source

    Source documentation

    Definition of function $f(n) := \sum_{1\leq k\leq n}\tau(2^k-1)$. Here $\tau$ is the divisor counting function, which is σ 0 in mathlib.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: Nat

    Proof uses: Finset.sum, Finset.Icc, OfNat.ofNat, ArithmeticFunction, ArithmeticFunction.sigma, HSub.hSub, HPow.hPow

    14 instances, coercions and auxiliary constants left out.

    def f (n : ℕ) : ℕ :=  ∑ k ∈ Finset.Icc 1 n, σ 0 (2^k - 1)
    …
  2. theorem Erdos893.erdos_893 Does the limit $\lim_{n\to\infty} \frac{f(2n)}{f(n)}$ tend to infinity? sorry line 47 source

    Source documentation

    Does the limit $\lim_{n\to\infty} \frac{f(2n)}{f(n)}$ tend to infinity?

    (Other finite limits have been ruled out by [KoLu25], see below)

    depends on sorry what this means

    Statement uses: Iff, True, Filter.Tendsto, Nat, Real, HDiv.hDiv, Erdos893.f, HMul.hMul, OfNat.ofNat, Filter.atTop

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    20 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_893 :
        answer(sorry) ↔ Tendsto (fun n : ℕ => (f (2 * n) : ℝ) / (f n : ℝ)) atTop atTop := by
    …

    Mentions: Erdos893.f

  3. theorem Erdos893.erdos_893.variants.unbounded Documented declaration: unbounded sorry line 58 source

    Source documentation

    Kovač and Luca [KoLu25] (building on a heuristic independently found by Cambie (personal communication)) have shown that there is no finite limit, in that $\lim_{n\to\infty} \frac{f(2n)}{f(n)}$ is unbounded.

    depends on sorry what this means

    Statement uses: Not, BddAbove, Real, Set.range, Nat, HDiv.hDiv, Erdos893.f, HMul.hMul, OfNat.ofNat

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    18 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_893.variants.unbounded :
       ¬ BddAbove (Set.range fun n : ℕ => (f (2 * n) : ℝ) / f n) := by
    …

    Mentions: Erdos893.f