FormalConjectures/ErdosProblems/688.lean
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5 declarations, 3 contain sorry, 0 declared as axioms
Erdős Problem 688
Reference:
- erdosproblems.com/688
- [Er80] Erdős, Paul, A survey of problems in combinatorial number theory. Ann. Discrete Math. (1980), 89-115.
Imports (1)
- def
Erdos688.Erdos688PropDefine line 38 sourceSource documentation
Define $\epsilon_n$ to be maximal such that there exists some choice of congruence class $a_p$ for all primes $n^{\epsilon_n} < p \leq n$ such that every integer in $[1,n]$ satisfies at least one of the congruences $\equiv a_p \pmod p$.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,RealProof uses:
Exists,LE.le,OfNat.ofNat,And,Nat.Prime,LT.lt,HPow.hPow,Nat.ModEq7 instances, coercions and auxiliary constants left out.
def Erdos688Prop (n : ℕ) (ε : ℝ) : Prop := …
- def
Erdos688.epsilonFunctionline 43 sourcestandard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,RealProof uses:
SupSet.sSup,Set.ofPred, Erdos688.Erdos688Prop1 instances, coercions and auxiliary constants left out.
- theorem
Erdos688.erdos_688.parts.iEstimate $\epsilon_n$ sorry line 49 sourceSource documentation
Estimate $\epsilon_n$.
depends on sorry what this means
Statement uses:
Asymptotics.IsTheta,Nat,Real,Filter.atTop, Erdos688.epsilonFunction,sorryAx,Bool.falseProof uses:
Lean.Name,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat5 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_688.parts.i : epsilonFunction =Θ[atTop] (answer(sorry) : ℕ → ℝ) := by …Mentions: Erdos688.epsilonFunction
- theorem
Erdos688.erdos_688.parts.iiIn particular, is it true that $\epsilon_n = o(1)$? sorry line 57 sourceSource documentation
In particular, is it true that $\epsilon_n = o(1)$?
depends on sorry what this means
Statement uses:
Iff,True,Asymptotics.IsLittleO,Nat,Real,Filter.atTop, Erdos688.epsilonFunction,OfNat.ofNatProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous9 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_688.parts.ii : answer(sorry) ↔ epsilonFunction =o[atTop] (fun (n : ℕ) ↦ (1 : ℝ)) := by …Mentions: Erdos688.epsilonFunction
- theorem
Erdos688.erdos_688.variants.lglglg_over_lglg_is_big_oErdős claims in [Er80] (p sorry line 66 sourceSource documentation
Erdős claims in [Er80] (p. 106) that it is not difficult to prove $\epsilon_n \gg \frac{\log\log\log n}{\log\log n}$.
depends on sorry what this means
Statement uses:
Asymptotics.IsBigO,Nat,Real,Filter.atTop,HDiv.hDiv,Real.log, Erdos688.epsilonFunctionProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat15 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_688.variants.lglglg_over_lglg_is_big_o : (fun (n : ℕ) ↦ (log (log (log (n : ℝ)))) / (log (log (n : ℝ)))) =O[atTop] epsilonFunction := by …Mentions: Erdos688.epsilonFunction