FormalConjectures/ErdosProblems/683.lean
Explanation legend Lean4 Domain Explanation Language (L4DEL)
L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.
- L4DEL
- Lean4 Domain Explanation Language
Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.
Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
5 declarations, 4 contain sorry, 0 declared as axioms
Erdős Problem 683
References:
- erdosproblems.com/683
- [Er34] Erdős, Paul, A Theorem of Sylvester and Schur. J. London Math. Soc. (1934), 282--288.
- [Er55d] Erdős, P., On consecutive integers. Nieuw Arch. Wisk. (3) (1955), 124--128.
- [Er79d] Erdős, P., Some unconventional problems in number theory. Acta Math. Acad. Sci. Hungar. (1979), 71-80.
- def
Erdos683.PLet $P(n, k)$ be the largest prime factor of $\binom{n}{k}$ line 41 sourceSource documentation
Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
NatProof uses:
Finset.sup,Nat.primeFactors,Nat.choose,id3 instances, coercions and auxiliary constants left out.
def P (n k : ℕ) : ℕ := (n.choose k).primeFactors.sup id …
- theorem
Erdos683.erdos_683Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$ sorry line 54 sourceSource documentation
Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$. There exists $c > 0$ such that $P(n, k) \ge \min(n - k + 1, k^{1 + c})$ for all $0 < k \le n/2$.
Erdős stated this for $1 \le k \le n$ with the bound $\min(n-k+1, k^{1+c})$ [Er79d]. The minimum is needed even for $k \le n/2$: at $n = 2k$ every prime factor of $\binom{2k}{k}$ is at most $2k$, so $P(n, k) \ge k^{1+c}$ fails for large $k$. The range $k \le n/2$ is natural (cf. #961 and the discussion).
L4DEL explanation
Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$. There exists $c > 0$ such that $P(n, k) \ge \min(n - k + 1, k^{1 + c})$ for all $0 < k \le n/2$. Erdős stated this for $1 \le k \le n$ with the bound $\min(n-k+1, k^{1+c})$ [Er79d]. The minimum is needed even for $k \le n/2$: at $n = 2k$ every prime factor of $\binom{2k}{k}$ is at most $2k$, so $P(n, k) \ge k^{1+c}$ fails for large $k$. The range $k \le n/2$ is natural (cf. #961 and the discussion).
Sources and attribution: Pinned Lean source (1646ca16afd6)
depends on sorry what this means
Statement uses:
Iff,True,Exists,Real,And,GT.gt,OfNat.ofNat,Nat,LT.lt,LE.le,HDiv.hDiv,GE.ge, Erdos683.P,Min.min,HAdd.hAdd,HSub.hSub,HPow.hPowProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous42 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_683 : answer(sorry) ↔ ∃ c > (0 : ℝ), ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 → (P n k : ℝ) ≥ min (↑(n - k + 1) : ℝ) ((k : ℝ) ^ (1 + c)) := by …Mentions: c, Erdos683.P
- theorem
Erdos683.erdos_683.variant.sylvester_schurSylvester and Schur [Er34] proved that $P(n, k) > k$ for $k \le n/2$ sorry line 63 sourceSource documentation
Sylvester and Schur [Er34] proved that $P(n, k) > k$ for $k \le n/2$.
depends on sorry what this means
Statement uses:
Nat,And,LT.lt,OfNat.ofNat,LE.le,HDiv.hDiv,GT.gt, Erdos683.PProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous10 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_683.variant.sylvester_schur : ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 → P n k > k := by …Mentions: Erdos683.P
- theorem
Erdos683.erdos_683.variant.erdos_logErdős [Er55d] improved this to $P(n, k) \gg \min(n - k + 1, k \log k)$ for $k \le n/2$ sorry line 72 sourceSource documentation
Erdős [Er55d] improved this to $P(n, k) \gg \min(n - k + 1, k \log k)$ for $k \le n/2$. The minimum cannot be dropped: at $n = 2k$ one has $P(n, k) \le 2k$.
depends on sorry what this means
Statement uses:
Exists,Real,And,GT.gt,OfNat.ofNat,Nat,LT.lt,LE.le,HDiv.hDiv,GE.ge, Erdos683.P,Min.min,HAdd.hAdd,HSub.hSub,HMul.hMul,Real.logProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous36 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_683.variant.erdos_log : ∃ c > 0, ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 → (P n k : ℝ) ≥ min (↑(n - k + 1) : ℝ) (c * k * Real.log k) := by …Mentions: c, Erdos683.P
- theorem
Erdos683.erdos_683.variant.exp_sqrtStandard heuristics suggest that $P(n, k) > \min(n - k + 1, e^{c\sqrt{k}})$ for some constant $c > 0$ sorry line 82 sourceSource documentation
Standard heuristics suggest that $P(n, k) > \min(n - k + 1, e^{c\sqrt{k}})$ for some constant $c > 0$.
depends on sorry what this means
Statement uses:
Exists,Real,And,GT.gt,OfNat.ofNat,Nat,LT.lt,LE.le,HDiv.hDiv, Erdos683.P,Min.min,HAdd.hAdd,HSub.hSub,Real.exp,HMul.hMul,Real.sqrtProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous34 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_683.variant.exp_sqrt : ∃ c > 0, ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 → (P n k : ℝ) > min (↑(n - k + 1) : ℝ) (Real.exp (c * Real.sqrt k)) := by …Mentions: c, Erdos683.P