FormalConjectures/ErdosProblems/683.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

5 declarations, 4 contain sorry, 0 declared as axioms

Erdős Problem 683

References:

Imports (2)
  1. def Erdos683.P Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$ line 41 source

    Source documentation

    Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: Nat

    Proof uses: Finset.sup, Nat.primeFactors, Nat.choose, id

    3 instances, coercions and auxiliary constants left out.

    def P (n k : ℕ) : ℕ := (n.choose k).primeFactors.sup id
    …
  2. theorem Erdos683.erdos_683 Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$ sorry line 54 source

    Source documentation

    Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$. There exists $c > 0$ such that $P(n, k) \ge \min(n - k + 1, k^{1 + c})$ for all $0 < k \le n/2$.

    Erdős stated this for $1 \le k \le n$ with the bound $\min(n-k+1, k^{1+c})$ [Er79d]. The minimum is needed even for $k \le n/2$: at $n = 2k$ every prime factor of $\binom{2k}{k}$ is at most $2k$, so $P(n, k) \ge k^{1+c}$ fails for large $k$. The range $k \le n/2$ is natural (cf. #961 and the discussion).

    L4DEL explanation

    Let $P(n, k)$ be the largest prime factor of $\binom{n}{k}$. There exists $c > 0$ such that $P(n, k) \ge \min(n - k + 1, k^{1 + c})$ for all $0 < k \le n/2$. Erdős stated this for $1 \le k \le n$ with the bound $\min(n-k+1, k^{1+c})$ [Er79d]. The minimum is needed even for $k \le n/2$: at $n = 2k$ every prime factor of $\binom{2k}{k}$ is at most $2k$, so $P(n, k) \ge k^{1+c}$ fails for large $k$. The range $k \le n/2$ is natural (cf. #961 and the discussion).

    Sources and attribution: Pinned Lean source (1646ca16afd6)

    depends on sorry what this means

    Statement uses: Iff, True, Exists, Real, And, GT.gt, OfNat.ofNat, Nat, LT.lt, LE.le, HDiv.hDiv, GE.ge, Erdos683.P, Min.min, HAdd.hAdd, HSub.hSub, HPow.hPow

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    42 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_683 : answer(sorry) ↔
        ∃ c > (0 : ℝ), ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 →
          (P n k : ℝ) ≥ min (↑(n - k + 1) : ℝ) ((k : ℝ) ^ (1 + c)) := by
    …

    Mentions: c, Erdos683.P

  3. theorem Erdos683.erdos_683.variant.sylvester_schur Sylvester and Schur [Er34] proved that $P(n, k) > k$ for $k \le n/2$ sorry line 63 source

    Source documentation

    Sylvester and Schur [Er34] proved that $P(n, k) > k$ for $k \le n/2$.

    depends on sorry what this means

    Statement uses: Nat, And, LT.lt, OfNat.ofNat, LE.le, HDiv.hDiv, GT.gt, Erdos683.P

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    10 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_683.variant.sylvester_schur :
        ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 → P n k > k := by
    …

    Mentions: Erdos683.P

  4. theorem Erdos683.erdos_683.variant.erdos_log Erdős [Er55d] improved this to $P(n, k) \gg \min(n - k + 1, k \log k)$ for $k \le n/2$ sorry line 72 source

    Source documentation

    Erdős [Er55d] improved this to $P(n, k) \gg \min(n - k + 1, k \log k)$ for $k \le n/2$. The minimum cannot be dropped: at $n = 2k$ one has $P(n, k) \le 2k$.

    depends on sorry what this means

    Statement uses: Exists, Real, And, GT.gt, OfNat.ofNat, Nat, LT.lt, LE.le, HDiv.hDiv, GE.ge, Erdos683.P, Min.min, HAdd.hAdd, HSub.hSub, HMul.hMul, Real.log

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    36 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_683.variant.erdos_log :
        ∃ c > 0, ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 →
          (P n k : ℝ) ≥ min (↑(n - k + 1) : ℝ) (c * k * Real.log k) := by
    …

    Mentions: c, Erdos683.P

  5. theorem Erdos683.erdos_683.variant.exp_sqrt Standard heuristics suggest that $P(n, k) > \min(n - k + 1, e^{c\sqrt{k}})$ for some constant $c > 0$ sorry line 82 source

    Source documentation

    Standard heuristics suggest that $P(n, k) > \min(n - k + 1, e^{c\sqrt{k}})$ for some constant $c > 0$.

    depends on sorry what this means

    Statement uses: Exists, Real, And, GT.gt, OfNat.ofNat, Nat, LT.lt, LE.le, HDiv.hDiv, Erdos683.P, Min.min, HAdd.hAdd, HSub.hSub, Real.exp, HMul.hMul, Real.sqrt

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    34 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_683.variant.exp_sqrt :
        ∃ c > 0, ∀ n k : ℕ, 0 < k ∧ k ≤ n / 2 →
          (P n k : ℝ) > min (↑(n - k + 1) : ℝ) (Real.exp (c * Real.sqrt k)) := by
    …

    Mentions: c, Erdos683.P