FormalConjectures/ErdosProblems/458.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

2 declarations, 1 contain sorry, 0 declared as axioms

Erdős Problem 458

Reference: erdosproblems.com/458

Imports (1)
  1. def Erdos458.lcm_upto The least common multiple of the integers in the set $\{1, \dots, n\}$ line 32 source

    Source documentation

    The least common multiple of the integers in the set $\{1, \dots, n\}$.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: Nat

    Proof uses: Finset.lcm, Finset.Icc, OfNat.ofNat, id

    6 instances, coercions and auxiliary constants left out.

    def lcm_upto (n : ℕ) : ℕ :=
    …
  2. theorem Erdos458.erdos_458 Let $\operatorname{lcm}(1, \dots, n)$ denote the least common multiple of $\{1, \dots, n\}$ sorry line 41 source

    Source documentation

    Let $\operatorname{lcm}(1, \dots, n)$ denote the least common multiple of $\{1, \dots, n\}$. Let $p_k$ be the $k$-th prime. Is it true that for all $k \geq 1$, $\operatorname{lcm}(1, \dots, p_{k+1}-1) < p_k \cdot \operatorname{lcm}(1, \dots, p_k)$?

    depends on sorry what this means

    Statement uses: Iff, True, Nat, LT.lt, Erdos458.lcm_upto, HSub.hSub, Nat.nth, Prime, HAdd.hAdd, OfNat.ofNat, HMul.hMul

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    18 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_458 :
        answer(sorry) ↔ ∀ k : ℕ, lcm_upto ((k + 1).nth Prime - 1)
         < k.nth Prime * lcm_upto (k.nth Prime) := by
    …

    Mentions: Erdos458.lcm_upto