FormalConjectures/ErdosProblems/430.lean
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4 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 430
References:
- erdosproblems.com/430
- [ErGr80] Erdős, P. and Graham, R., Old and new problems and results in combinatorial number theory. Monographies de L'Enseignement Mathematique (1980).
The question is equivalent to the first part of Erdős Problem 385 (an observation of Sarosh Adenwalla recorded on both problem pages).
Imports (1)
- def
Erdos430.termsThe terms of the sequence of Erdős Problem 430 for a given $n$: the integers $m$ with $1 < m < n$ all of whose prime factors are $> n - m$ line 48 sourceSource documentation
The terms of the sequence of Erdős Problem 430 for a given $n$: the integers $m$ with $1 < m < n$ all of whose prime factors are $> n - m$.
The decreasing sequence $a_1 > a_2 > \cdots$ of the problem lists the elements of this set in decreasing order: $a_1 = n - 1$ is its largest element and $a_k$ is its largest element below $a_{k-1}$. The integer $1$ has no prime factors and is not a term of the sequence, which stops instead, as in the example on erdosproblems.com: for $n = 8$ the sequence is $7, 5$.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,FinsetProof uses:
Finset.filter,Membership.mem,Nat.primeFactors,LT.lt,HSub.hSub,Finset.Ioo,OfNat.ofNat10 instances, coercions and auxiliary constants left out.
def terms (n : ℕ) : Finset ℕ := (Finset.Ioo 1 n).filter fun m => ∀ p ∈ m.primeFactors, n - m < p …
- theorem
Erdos430.terms_eightFor example if $n=8$ we have $a_1=7$ and $a_2=5$ and then must stop line 52 sourceSource documentation
For example if $n=8$ we have $a_1=7$ and $a_2=5$ and then must stop.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Eq,Finset,Nat, Erdos430.terms,OfNat.ofNat,Insert.insert,Singleton.singleton5 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem terms_eight : terms 8 = {5, 7} := by …Mentions: Erdos430.terms
- theorem
Erdos430.isGreatest_sub_oneThe first term of the sequence is $a_1 = n - 1$, the largest element ofterms nline 57 sourceSource documentation
The first term of the sequence is $a_1 = n - 1$, the largest element of
terms n.standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,IsGreatest,Finset, Erdos430.terms,HSub.hSubProof uses:
And.intro,Membership.mem,Set,upperBounds,Eq.mpr,And,LT.lt,Nat.primeFactors,id,Eq,Eq.trans,Finset.filter,Finset.Ioo,congrFun',congrArg,Decidable.byContradiction,Not,Nat.Prime.one_lt,Nat.prime_of_mem_primeFactors,Eq.mp28 instances, coercions and auxiliary constants left out.
Tactic trace: 11 steps
Open to load the checked before-and-after goal states.
theorem isGreatest_sub_one {n : ℕ} (hn : 3 ≤ n) : IsGreatest (terms n : Set ℕ) (n - 1) := by …Mentions: Erdos430.terms
- theorem
Erdos430.erdos_430Fix some integer sorry line 74 sourceSource documentation
Fix some integer $n$ and define a decreasing sequence in $[1,n)$ by $a_1=n-1$ and, for $k\geq 2$, letting $a_k$ be the greatest integer in $[1,a_{k-1})$ such that all of the prime factors of $a_k$ are $>n-a_k$.
Is it true that, for sufficiently large $n$, not all of this sequence can be prime?
depends on sorry what this means
Statement uses:
Iff,True,Filter.Eventually,Nat,Not,Membership.mem,Finset, Erdos430.terms,Nat.Prime,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat7 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_430 : answer(sorry) ↔ ∀ᶠ n in atTop, ¬ ∀ m ∈ terms n, m.Prime := by …
Mentions: Erdos430.terms