FormalConjectures/ErdosProblems/414.lean
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2 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 414
Reference: erdosproblems.com/414
Imports (1)
- def
Erdos414.hThe auxiliary function $h(n) = n + τ(n)$ (where $τ(n) counts the number of divisors of $n$) line 32 sourceSource comment
The auxiliary function $h(n) = n + τ(n)$ (where $τ(n) counts the number of divisors of $n$)standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
NatProof uses:
HAdd.hAdd,Finset.card,Nat.divisors2 instances, coercions and auxiliary constants left out.
def h (n : ℕ) : ℕ := n + n.divisors.card …
- theorem
Erdos414.erdos_414Let $h_1(n) = h(n)$ and $h_k(n) = h(h_{k-1}(n))$ sorry line 39 sourceSource documentation
Let $h_1(n) = h(n)$ and $h_k(n) = h(h_{k-1}(n))$. Is it true, for any $m,n$, there exist $i$ and $j$ such that $h_i(m) = h_j(n)$?
depends on sorry what this means
Statement uses:
Iff,True,Nat,GT.gt,OfNat.ofNat,Exists,Eq,Nat.iterate, Erdos414.hProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous4 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_414 : answer(sorry) ↔ ∀ᵉ (m > 0) (n > 0), ∃ i j, h^[i] m = h^[j] n := by …
Mentions: Erdos414.h