FormalConjectures/ErdosProblems/354.lean
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4 declarations, 2 contain sorry, 0 declared as axioms
Erdős Problem 354
Reference: erdosproblems.com/354
Imports (1)
- def
Erdos354.FloorMultiplesThe sequence⌊a⌋, ⌊γ * a⌋, ⌊γ ^ 2 * a⌋, ..., ⌊γ ^ i * a⌋, ...line 30 sourceSource documentation
The sequence
⌊a⌋, ⌊γ * a⌋, ⌊γ ^ 2 * a⌋, ..., ⌊γ ^ i * a⌋, ....standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Real,Nat,IntProof uses:
Int.floor,HMul.hMul,HPow.hPow9 instances, coercions and auxiliary constants left out.
noncomputable def FloorMultiples (a γ : ℝ) (n : ℕ) : ℤ := ⌊γ ^ n * a⌋
- def
Erdos354.FloorMultiples.interleaveThe sequence `⌊a⌋, ⌊b⌋, ⌊γ * a⌋, ⌊γ * b⌋, line 33 sourceSource documentation
The sequence
⌊a⌋, ⌊b⌋, ⌊γ * a⌋, ⌊γ * b⌋, ... ⌊γ ^ i * a⌋, ⌊γ ^ i * b⌋, ...standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Real,Nat,IntProof uses:
ite,Eq,HMod.hMod,OfNat.ofNat, Erdos354.FloorMultiples,HDiv.hDiv6 instances, coercions and auxiliary constants left out.
noncomputable def FloorMultiples.interleave (a b γ : ℝ) (n : ℕ) : ℤ := …
- theorem
Erdos354.erdos_354.parts.iLet $\alpha,\beta\in \mathbb{R}_{>0}$ such that $\alpha/\beta$ is irrational sorry line 43 sourceSource documentation
Let $\alpha,\beta\in \mathbb{R}_{>0}$ such that $\alpha/\beta$ is irrational. Is the multiset $$\{ \lfloor \alpha\rfloor,\lfloor 2\alpha\rfloor,\lfloor 4\alpha\rfloor,\ldots\}\cup \{ \lfloor \beta\rfloor,\lfloor 2\beta\rfloor,\lfloor 4\beta\rfloor,\ldots\}$$ complete?
depends on sorry what this means
Statement uses:
Iff,True,Real,GT.gt,OfNat.ofNat,Irrational,HDiv.hDiv, IsAddCompleteNatSeq',Int, Erdos354.FloorMultiples.interleave,NatProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous36 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_354.parts.i : answer(sorry) ↔ ∀ᵉ (α > 0) (β > 0), Irrational (α / β) → IsAddCompleteNatSeq' (FloorMultiples.interleave α β 2) := by …Mentions: IsAddCompleteNatSeq', Erdos354.FloorMultiples.interleave
- theorem
Erdos354.erdos_354.parts.iiLet $\alpha,\beta\in \mathbb{R}_{>0}$ such that $\alpha/\beta$ is irrational sorry line 51 sourceSource documentation
Let $\alpha,\beta\in \mathbb{R}_{>0}$ such that $\alpha/\beta$ is irrational. Is $$\{ \lfloor \alpha\rfloor,\lfloor \gamma\alpha\rfloor,\lfloor \gamma^2\alpha\rfloor,\ldots\}\cup \{ \lfloor \beta\rfloor,\lfloor \gamma\beta\rfloor,\lfloor \gamma^2\beta\rfloor,\ldots\}$$ complete?
depends on sorry what this means
Statement uses:
Iff,True,Exists,Real,And,Membership.mem,Set,Set.Ioo,OfNat.ofNat,Nat,GT.gt,Irrational,HDiv.hDiv, IsAddCompleteNatSeq',Int, Erdos354.FloorMultiples.interleaveProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous44 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_354.parts.ii : answer(sorry) ↔ ∃ γ ∈ Set.Ioo (1 : ℝ) 2, ∀ᵉ (α > 0) (β > 0), Irrational (α / β) → IsAddCompleteNatSeq' (FloorMultiples.interleave α β γ) := by …Mentions: IsAddCompleteNatSeq', Erdos354.FloorMultiples.interleave