FormalConjectures/ErdosProblems/292.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

6 declarations, 5 contain sorry, 0 declared as axioms

Erdős Problem 292

References:

Imports (1)
  1. def Erdos292.A The set $A$ of $n\in \mathbb{N}$ such that there exist $1\leq m_1<\cdots <m_k=n$ with $\sum\tfrac{1}{m_i}=1$ line 38 source

    Source documentation

    The set $A$ of $n\in \mathbb{N}$ such that there exist $1\leq m_1<\cdots <m_k=n$ with $\sum\tfrac{1}{m_i}=1$.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: Set, Nat

    Proof uses: Set.ofPred, Exists, Finset, And, LE.le, Finset.Icc, OfNat.ofNat, Membership.mem, Eq, Rat, Finset.sum, HDiv.hDiv

    14 instances, coercions and auxiliary constants left out.

    def A : Set ℕ :=
    …
  2. theorem Erdos292.erdos_292 sorry line 59 source

    depends on sorry what this means

    Statement uses: Iff, True, Set.HasDensity, Nat, Erdos292.A, OfNat.ofNat, Real, Set.univ

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    13 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

  3. theorem Erdos292.erdos_292.variants.martin Martin [Ma00] proved that if $B=\mathbb{N}\backslash A$ then $\frac{\lvert B\cap [1,x]\rvert}{x}\asymp \frac{\log\log x}{\log x}$ sorry line 65 source

    Source documentation

    Martin [Ma00] proved that if $B=\mathbb{N}\backslash A$ then $\frac{\lvert B\cap [1,x]\rvert}{x}\asymp \frac{\log\log x}{\log x}$.

    depends on sorry what this means

    Statement uses: Asymptotics.IsTheta, Nat, Real, Filter.atTop, HDiv.hDiv, Set.ncard, Inter.inter, Set, Compl.compl, Erdos292.A, Set.Icc, OfNat.ofNat, Real.log

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    20 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_292.variants.martin :
        (fun x : ℕ ↦ ((Aᶜ ∩ Set.Icc 1 x).ncard : ℝ) / x) =Θ[atTop]
          fun x ↦ Real.log (Real.log x) / Real.log x := by
    …
  4. theorem Erdos292.erdos_292.variants.mul Straus observed that $A$ is closed under multiplication sorry line 72 source

    Source documentation

    Straus observed that $A$ is closed under multiplication.

    depends on sorry what this means

    Statement uses: Nat, Membership.mem, Set, Erdos292.A, HMul.hMul

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous, OfNat.ofNat

    7 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_292.variants.mul : ∀ m ∈ A, ∀ n ∈ A, m * n ∈ A := by
    …

    Mentions: Erdos292.A

  5. theorem Erdos292.erdos_292.variants.prime_pow $A$ does not contain any prime power sorry line 77 source

    Source documentation

    $A$ does not contain any prime power.

    depends on sorry what this means

    Statement uses: Nat, Membership.mem, Set, Erdos292.A, Not, IsPrimePow

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous, OfNat.ofNat

    5 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_292.variants.prime_pow : ∀ n ∈ A, ¬ IsPrimePow n := by
    …

    Mentions: Erdos292.A

  6. theorem Erdos292.erdos_292.variants.two_mul van Doorn observed that if $n\in A$ (with $n>1$) then $2n\in A$ also sorry line 82 source

    Source documentation

    van Doorn observed that if $n\in A$ (with $n>1$) then $2n\in A$ also.

    depends on sorry what this means

    Statement uses: Nat, Membership.mem, Set, Erdos292.A, LT.lt, OfNat.ofNat, HMul.hMul

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    10 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_292.variants.two_mul : ∀ n ∈ A, 1 < n → 2 * n ∈ A := by
    …

    Mentions: Erdos292.A