FormalConjectures/ErdosProblems/208.lean
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4 declarations, 3 contain sorry, 0 declared as axioms
Erdős Problem 208
Reference: erdosproblems.com/208
Imports (1)
- def
Erdos208.erdos208.sThe sequence of squarefree numbers, denoted bysas in Erdős problem 208 line 32 sourceSource documentation
The sequence of squarefree numbers, denoted by
sas in Erdős problem 208.standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
NatProof uses:
Nat.nth,Squarefree1 instances, coercions and auxiliary constants left out.
noncomputable def erdos208.s : ℕ → ℕ := Nat.nth Squarefree …
- theorem
Erdos208.erdos_208.parts.iLet $s_1 < s_2 < \dots$ be the sequence of squarefree numbers sorry line 41 sourceSource documentation
Let $s_1 < s_2 < \dots$ be the sequence of squarefree numbers. Is it true that for any $\epsilon > 0$ and large $n$, $s_{n+1} - s_n \ll_\epsilon s_n^\epsilon$?
depends on sorry what this means
Statement uses:
Iff,True,Real,GT.gt,OfNat.ofNat,Asymptotics.IsBigO,Nat,Filter.atTop,HSub.hSub, Erdos208.erdos208.s,HAdd.hAdd,HPow.hPowProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous28 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_208.parts.i : answer(sorry) ↔ ∀ ε > (0 : ℝ), (fun n => (s (n + 1) - s n : ℝ)) =O[atTop] (fun n => (s n : ℝ)^ε) := by sorry … - theorem
Erdos208.erdos_208.parts.iiLet $s_1 < s_2 < \dots$ be the sequence of squarefree numbers sorry line 49 sourceSource documentation
Let $s_1 < s_2 < \dots$ be the sequence of squarefree numbers. Is it true that $s_{n + 1} - s_n \le (1 + o(1)) \cdot (\pi^2 / 6) \cdot \log (s_n) / \log (\log (s_n))$?
depends on sorry what this means
Statement uses:
Iff,True,Exists,Nat,Real,And,Asymptotics.IsLittleO,Filter.atTop,OfNat.ofNat,Filter.Eventually,LE.le,HSub.hSub, Erdos208.erdos208.s,HAdd.hAdd,HDiv.hDiv,HMul.hMul,HPow.hPow,Real.pi,Real.logProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous52 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_208.parts.ii : answer(sorry) ↔ ∃ (c : ℕ → ℝ), (c =o[atTop] (1 : ℕ → ℝ)) ∧ ∀ᶠ n in atTop, s (n + 1) - s n ≤ (1 + (c n)) * (π^2 / 6) * log (s n) / log (log (s n)) := by …Mentions: c
- theorem
Erdos208.erdos_208.variants.log_boundIn [Er79] Erdős says perhaps $s_{n+1} - s_n \ll \log s_n$, but he is 'very doubtful' sorry line 59 sourceSource documentation
In [Er79] Erdős says perhaps $s_{n+1} - s_n \ll \log s_n$, but he is 'very doubtful'.
[Er79] Erdős, Paul, Some unconventional problems in number theory. Math. Mag. (1979), 67-70.
depends on sorry what this means
Statement uses:
Asymptotics.IsBigO,Nat,Real,Filter.atTop,HSub.hSub, Erdos208.erdos208.s,HAdd.hAdd,OfNat.ofNat,Real.logProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous18 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_208.variants.log_bound : (fun n ↦ (s (n + 1) - s n : ℝ)) =O[atTop] fun n ↦ log (s n) := by sorry …