FormalConjectures/ErdosProblems/188.lean
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4 declarations, 3 contain sorry, 0 declared as axioms
Erdős Problem 188
References:
- erdosproblems.com/188
- [EGMRSS75] Erdős, P. and Graham, R. L. and Montgomery, P. and Rothschild, B. L. and Spencer, J. and Straus, E. G., Euclidean {R}amsey theorems. {II}. (1975), 529--557.
- [Ts17] Tsaturian, Sergei, A {E}uclidean {R}amsey result in the plane. Electron. J. Combin. (2017), Paper No. 4.35, 9.
Imports (1)
Imported by 1 file
- def
Erdos188.sThe set of numbers line 39 sourceSource documentation
The set of numbers $k$ such that $\mathbb{R}^2$ can be red/blue coloured with no pair of red points unit distance apart, and no $k$-term arithmetic progression of blue points with distance 1.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Set,NatProof uses:
Set.ofPred,Exists,Complex,And,Set.Pairwise,SDiff.sdiff,Set.univ,Ne,Real,Dist.dist,OfNat.ofNat,Not,LE.le,Eq,Norm.norm, Set.IsAPOfLengthWith,ENat14 instances, coercions and auxiliary constants left out.
def s := { k : ℕ | ∃ blue : Set ℂ, … - theorem
Erdos188.erdos_188What is the smallest sorry line 48 sourceSource documentation
What is the smallest $k$ such that $\mathbb{R}^2$ can be red/blue coloured with no pair of red points unit distance apart, and no $k$-term arithmetic progression of blue points with distance 1?
depends on sorry what this means
Statement uses:
IsLeast,Nat, Erdos188.s,sorryAx,Bool.falseProof uses:
Lean.Name,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat3 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_188 : IsLeast s answer(sorry) := by …
Mentions: Erdos188.s
- theorem
Erdos188.erdos_188.variants.nonemptyOld and new problems and results in combinatorial number theory by Erdős & Graham (Page 14, 15): It has been shown that there is a large sorry line 59 sourceSource documentation
Old and new problems and results in combinatorial number theory by Erdős & Graham (Page 14, 15):
It has been shown that there is a large $M$ so that it is possible to partition $\mathbb{E}^2$ into two sets $A$ and $B$ so that $A$ contains no pair of points with distance 1 and $B$ contains no A.P. of length $M$.
depends on sorry what this means
Statement uses:
Set.Nonempty,Nat, Erdos188.sProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat1 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_188.variants.nonempty : s.Nonempty := by …
- theorem
Erdos188.erdos_188.variants.estimateOld and new problems and results in combinatorial number theory by Erdős & Graham (Page 15): How small can $M$ be made? sorry line 69 sourceSource documentation
Old and new problems and results in combinatorial number theory by Erdős & Graham (Page 15):
How small can $M$ be made? The only estimate currently known is that $M \le 10000000$ (more or less). In the other direction, it has just been shown by R. Juhász [Ju (79)] that we must have $M \ge 5$.
depends on sorry what this means
Statement uses:
And,Nat,Membership.mem,Set, Erdos188.s,LE.le,OfNat.ofNat,ExistsProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous6 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_188.variants.estimate : (∀ k, k ∈ s → 5 ≤ k) ∧ (∃ k ∈ s, k ≤ 10000000) := by …
Mentions: Erdos188.s