FormalConjectures/ErdosProblems/119.lean
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5 declarations, 3 contain sorry, 0 declared as axioms
Erdős Problem 119
References:
- erdosproblems.com/119
- [Be91] Beck, J., The modulus of polynomials with zeros on the unit circle: A problem of Erdős. Annals of Math. (1991), 609-651.
- [Er57] Erdős, Paul, Some unsolved problems. Michigan Math. J. (1957), 291-300.
- [Er61] Erdős, Paul, Some unsolved problems. Magyar Tud. Akad. Mat. Kutató Int. Közl. (1961), 221-254.
- [Er64b] Erdős, P., Problems and results on diophantine approximations. Compositio Math. (1964), 52-65.
- [Er82e] Erdős, Paul, Some of my favourite problems which recently have been solved. (1982), 59--79.
- [Er90] Erdős, Paul, Some of my favourite unsolved problems. A tribute to Paul Erdős (1990), 467-478.
- [Er97f] Erdős, Paul, Some unsolved problems. Combinatorics, geometry and probability (Cambridge, 1993) (1997), 1-10.
- [Ha74] Hayman, W. K., Research problems in function theory: new problems. (1974), 155--180.
- [Li77] Linden, C. N., The modulus of polynomials with zeros on the unit circle. Bull. London Math. Soc. (1977), 65--69.
- [Va99] Various, Some of Paul's favorite problems. Booklet produced for the conference "Paul Erdős and his mathematics", Budapest, July 1999 (1999).
- [Wa80] Wagner, Gerold, On a problem of Erdős in {D}iophantine approximation. Bull. London Math. Soc. (1980), 81--88.
Imports (1)
- def
Erdos119.pLet $z_i$ be an infinite sequence of complex numbers such that $|z_i| = 1$ for all $i \geq 1$ line 60 sourceSource documentation
Let $z_i$ be an infinite sequence of complex numbers such that $|z_i| = 1$ for all $i \geq 1$. For $n \geq 1$ let $p_n(z) = \prod_{i \leq n} (z - z_i)$.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,ComplexProof uses:
Finset.prod,Finset.range,HSub.hSub4 instances, coercions and auxiliary constants left out.
noncomputable def p (z : ℕ → ℂ) (n : ℕ) : ℂ → ℂ := …
- def
Erdos119.MLet $M_n = \max_{|z| = 1} |p_n(z)|$ line 64 sourceSource documentation
Let $M_n = \max_{|z| = 1} |p_n(z)|$.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,Complex,RealProof uses:
SupSet.sSup,Set.ofPred,Exists,Eq,Norm.norm,OfNat.ofNat, Erdos119.p4 instances, coercions and auxiliary constants left out.
noncomputable def M (z : ℕ → ℂ) (n : ℕ) : ℝ := …
- theorem
Erdos119.erdos_119.parts.iIs it true that $\limsup M_n = \infty$? sorry line 76 sourceSource documentation
Is it true that $\limsup M_n = \infty$?
This is Problem 4.1 in [Ha74] where it is attributed to Erdős.
The weaker conjecture that $\limsup M_n=\infty$ was proved by Wagner [Wa80], who show that there is some $c>0$ with $M_n>(\log n)^c$ infinitely often.
depends on sorry what this means
Statement uses:
Iff,True,Nat,Complex,Eq,Real,Norm.norm,OfNat.ofNat,EReal,Filter.limsup, Erdos119.M,Filter.atTop,Top.topProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous21 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_119.parts.i : answer(True) ↔ ∀ (z : ℕ → ℂ) (hz : ∀ i : ℕ, ‖z i‖ = 1), atTop.limsup (fun n => (M z n : EReal)) = ⊤ := by …Mentions: Erdos119.M
- theorem
Erdos119.erdos_119.parts.iiIs it true that there exists $c > 0$ such that for infinitely many $n$ we have $M_n > n^c$? sorry line 88 sourceSource documentation
Is it true that there exists $c > 0$ such that for infinitely many $n$ we have $M_n > n^c$?
The second question was answered by Beck [Be91], who proved that there exists some $c>0$ such that $\max_{n\leq N} M_n > N^c$.
depends on sorry what this means
Statement uses:
Iff,True,Nat,Complex,Eq,Real,Norm.norm,OfNat.ofNat,Exists,GT.gt,Infinite,Set.ofPred, Erdos119.M,HPow.hPowProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous23 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_119.parts.ii : answer(True) ↔ ∀ (z : ℕ → ℂ) (hz : ∀ i : ℕ, ‖z i‖ = 1), ∃ (c : ℝ) (hc : c > 0), Infinite {n : ℕ | M z n > n ^ c} := by …Mentions: Erdos119.erdos_119.parts.i, c, Erdos119.M
- theorem
Erdos119.erdos_119.parts.iiiIs it true that there exists $c > 0$ such that, for all large $n$, $\sum_{k \leq n} M_k > n^{1 + c}$? sorry line 101 sourceSource documentation
Is it true that there exists $c > 0$ such that, for all large $n$, $\sum_{k \leq n} M_k > n^{1 + c}$?
The $100 prize was offered for the third question in [Er97f]. This was resolved by GPT 5.6 and Korsky (see the proof claims), who proved that $\sum_{k\leq n}M_k \gg \frac{n^{5/4}}{\sqrt{\log n}}$ (and hence for infinitely many $n$ we have $M_n> n^{1/4-o(1)}$).
depends on sorry what this means
Statement uses:
Iff,True,Nat,Complex,Eq,Real,Norm.norm,OfNat.ofNat,Exists,GT.gt,Filter.Eventually,Finset.sum,Finset.range, Erdos119.M,HPow.hPow,HAdd.hAdd,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous29 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_119.parts.iii : answer(True) ↔ ∀ (z : ℕ → ℂ) (hz : ∀ i : ℕ, ‖z i‖ = 1), ∃ (c : ℝ) (hc : c > 0), ∀ᶠ n in atTop, ∑ k ∈ range n, M z k > n ^ (1 + c) := by …Mentions: Erdos119.erdos_119.parts.i, c, Erdos119.M