FormalConjectures/ErdosProblems/1106.lean

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L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

3 declarations, 2 contain sorry, 0 declared as axioms

Erdős Problem 1106

References:

Imports (1)
  1. def Erdos1106.p The partition function p(n) is the number of ways to write n as a sum of positive integers (where the order of the summands does not matter) line 37 source

    Source documentation

    The partition function p(n) is the number of ways to write n as a sum of positive integers (where the order of the summands does not matter).

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: Nat

    Proof uses: Fintype.card, Nat.Partition

    1 instances, coercions and auxiliary constants left out.

    def p : ℕ → ℕ := fun n => Fintype.card (Nat.Partition n)
    …
  2. theorem Erdos1106.erdos_1106.parts.i Let $p(n)$ be the partition number of $n$ and $F(n)$ be the number of distinct prime factors of $∏_{i= 1} ^ {n} p(n)$, then $F(n)$ tends to infinity when $n$ tends to infinity sorry line 46 source

    Source documentation

    Let $p(n)$ be the partition number of $n$ and $F(n)$ be the number of distinct prime factors of $∏_{i= 1} ^ {n} p(n)$, then $F(n)$ tends to infinity when $n$ tends to infinity.

    The answer is yes: Schinzel and Wirsing [ScWi87] proved $F(n) \gg \log n$.

    depends on sorry what this means

    Statement uses: Iff, True, Filter.Tendsto, Nat, Finset.card, Nat.primeFactors, Finset.prod, Finset.Icc, OfNat.ofNat, Erdos1106.p, Filter.atTop

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    8 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_1106.parts.i :
        answer(True) ↔ Tendsto (fun n => #(∏ i ∈ Icc 1 n, p i).primeFactors) atTop atTop := by
    …

    Mentions: Erdos1106.p

  3. theorem Erdos1106.erdos_1106.parts.ii Let $p(n)$ be the partition number of $n$ and $F(n)$ be the number of distinct prime factors of $∏_{i= 1} ^ {n} p(n)$, $F(n)>n$ for sufficiently large $n$ sorry line 55 source

    Source documentation

    Let $p(n)$ be the partition number of $n$ and $F(n)$ be the number of distinct prime factors of $∏_{i= 1} ^ {n} p(n)$, $F(n)>n$ for sufficiently large $n$.

    depends on sorry what this means

    Statement uses: Iff, True, Filter.Eventually, Nat, GT.gt, Finset.card, Nat.primeFactors, Finset.prod, Finset.Icc, OfNat.ofNat, Erdos1106.p, Filter.atTop

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    10 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_1106.parts.ii :
        answer(sorry) ↔ ∀ᶠ n in atTop, #(∏ i ∈ Icc 1 n, p i).primeFactors > n := by
    …

    Mentions: Erdos1106.erdos_1106.parts.i, Erdos1106.p