FormalConjectures/ErdosProblems/1067.lean

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L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

3 declarations, 2 contain sorry, 0 declared as axioms

Erdős Problem 1067

References:

Imports (1)
Imported by 1 file
  1. def Erdos1067.InfinitelyEdgeConnected A graph is infinitely edge-connected if to disconnect the graph requires deleting infinitely many edges line 46 source

    Source documentation

    A graph is infinitely edge-connected if to disconnect the graph requires deleting infinitely many edges. In other words, removing any finite set of edges leaves the graph connected.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: SimpleGraph

    Proof uses: Set, Sym2, Set.Finite, SimpleGraph.Connected, SimpleGraph.deleteEdges

    def InfinitelyEdgeConnected {V : Type*} (G : SimpleGraph V) : Prop :=
    …
  2. theorem Erdos1067.erdos_1067 Does every graph with chromatic number $\aleph_1$ contain an infinitely connected subgraph with chromatic number $\aleph_1$? sorry line 60 source

    Source documentation

    Does every graph with chromatic number $\aleph_1$ contain an infinitely connected subgraph with chromatic number $\aleph_1$?

    Komjáth [Ko13] proved that it is consistent that the answer is no. This was improved by Soukup [So15], who constructed a counterexample using no extra set-theoretical assumptions. A simpler elementary example was given by Bowler and Pitz [BoPi24].

    This was formalized in Lean by Alexeev using Aristotle and Aleph Prover.

    depends on sorry what this means

    Statement uses: Iff, False, SimpleGraph, Eq, Cardinal, SimpleGraph.chromaticCardinal, OrderEmbedding, Ordinal, Cardinal.aleph, OfNat.ofNat, Exists, SimpleGraph.Subgraph, And, SimpleGraph.Subgraph.verts, SimpleGraph.Subgraph.coe, SimpleGraph.InfinitelyConnected

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous, Nat

    19 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_1067 :
        answer(False) ↔ ∀ (V : Type) (G : SimpleGraph V), G.chromaticCardinal = ℵ_ 1 →
          ∃ (H : G.Subgraph), H.coe.chromaticCardinal = ℵ_ 1 ∧ InfinitelyConnected H.coe := by
    …
  3. theorem Erdos1067.erdos_1067.variants.infinite_edge_connectivity Does every graph with chromatic number $\aleph_1$ contain an infinitely edge-connected subgraph with chromatic number $\aleph_1$? sorry line 73 source

    Source documentation

    Does every graph with chromatic number $\aleph_1$ contain an infinitely edge-connected subgraph with chromatic number $\aleph_1$?

    Thomassen [Th17] proved that the answer is yes: every graph of uncountable chromatic number has a subgraph with infinite edge-connectivity and uncountable chromatic number.

    depends on sorry what this means

    Statement uses: Iff, True, SimpleGraph, Eq, Cardinal, SimpleGraph.chromaticCardinal, OrderEmbedding, Ordinal, Cardinal.aleph, OfNat.ofNat, Exists, SimpleGraph.Subgraph, And, SimpleGraph.Subgraph.verts, SimpleGraph.Subgraph.coe, Erdos1067.InfinitelyEdgeConnected

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous, Nat

    19 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_1067.variants.infinite_edge_connectivity :
        answer(True) ↔ ∀ (V : Type) (G : SimpleGraph V), G.chromaticCardinal = ℵ_ 1 →
          ∃ (H : G.Subgraph), H.coe.chromaticCardinal = ℵ_ 1 ∧ InfinitelyEdgeConnected H.coe := by
    …

    Mentions: Erdos1067.InfinitelyEdgeConnected