FormalConjectures/ErdosProblems/1067.lean
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3 declarations, 2 contain sorry, 0 declared as axioms
Erdős Problem 1067
References:
- erdosproblems.com/1067
- [BoPi24] N. Bowler and M. Pitz, A note on uncountably chromatic graphs. arXiv:2402.05984 (2024).
- [ErHa66] Erdős, P. and Hajnal, A., On chromatic number of graphs and set-systems. Acta Math. Acad. Sci. Hungar. (1966), 61-99.
- [Ko13] Komjáth, Péter, A note on chromatic number and connectivity of infinite graphs. Israel J. Math. (2013), 499--506.
- [So15] Soukup, Dániel T., Trees, ladders and graphs. J. Combin. Theory Ser. B (2015), 96--116.
- [Th17] Thomassen, Carsten, Infinitely connected subgraphs in graphs of uncountable chromatic number. Combinatorica (2017), 785--793.
Imports (1)
Imported by 1 file
- def
Erdos1067.InfinitelyEdgeConnectedA graph is infinitely edge-connected if to disconnect the graph requires deleting infinitely many edges line 46 sourceSource documentation
A graph is infinitely edge-connected if to disconnect the graph requires deleting infinitely many edges. In other words, removing any finite set of edges leaves the graph connected.
standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
SimpleGraphProof uses:
Set,Sym2,Set.Finite,SimpleGraph.Connected,SimpleGraph.deleteEdgesdef InfinitelyEdgeConnected {V : Type*} (G : SimpleGraph V) : Prop := … - theorem
Erdos1067.erdos_1067Does every graph with chromatic number $\aleph_1$ contain an infinitely connected subgraph with chromatic number $\aleph_1$? sorry line 60 sourceSource documentation
Does every graph with chromatic number $\aleph_1$ contain an infinitely connected subgraph with chromatic number $\aleph_1$?
Komjáth [Ko13] proved that it is consistent that the answer is no. This was improved by Soukup [So15], who constructed a counterexample using no extra set-theoretical assumptions. A simpler elementary example was given by Bowler and Pitz [BoPi24].
This was formalized in Lean by Alexeev using Aristotle and Aleph Prover.
depends on sorry what this means
Statement uses:
Iff,False,SimpleGraph,Eq,Cardinal, SimpleGraph.chromaticCardinal,OrderEmbedding,Ordinal,Cardinal.aleph,OfNat.ofNat,Exists,SimpleGraph.Subgraph,And,SimpleGraph.Subgraph.verts,SimpleGraph.Subgraph.coe, SimpleGraph.InfinitelyConnectedProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,Nat19 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_1067 : answer(False) ↔ ∀ (V : Type) (G : SimpleGraph V), G.chromaticCardinal = ℵ_ 1 → ∃ (H : G.Subgraph), H.coe.chromaticCardinal = ℵ_ 1 ∧ InfinitelyConnected H.coe := by … - theorem
Erdos1067.erdos_1067.variants.infinite_edge_connectivityDoes every graph with chromatic number $\aleph_1$ contain an infinitely edge-connected subgraph with chromatic number $\aleph_1$? sorry line 73 sourceSource documentation
Does every graph with chromatic number $\aleph_1$ contain an infinitely edge-connected subgraph with chromatic number $\aleph_1$?
Thomassen [Th17] proved that the answer is yes: every graph of uncountable chromatic number has a subgraph with infinite edge-connectivity and uncountable chromatic number.
depends on sorry what this means
Statement uses:
Iff,True,SimpleGraph,Eq,Cardinal, SimpleGraph.chromaticCardinal,OrderEmbedding,Ordinal,Cardinal.aleph,OfNat.ofNat,Exists,SimpleGraph.Subgraph,And,SimpleGraph.Subgraph.verts,SimpleGraph.Subgraph.coe, Erdos1067.InfinitelyEdgeConnectedProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,Nat19 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_1067.variants.infinite_edge_connectivity : answer(True) ↔ ∀ (V : Type) (G : SimpleGraph V), G.chromaticCardinal = ℵ_ 1 → ∃ (H : G.Subgraph), H.coe.chromaticCardinal = ℵ_ 1 ∧ InfinitelyEdgeConnected H.coe := by …Mentions: Erdos1067.InfinitelyEdgeConnected