FormalConjectures/Books/BugeaudDistributionModuloOne/Problem10_32.lean
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3 declarations, 1 contain sorry, 0 declared as axioms
Bugeaud Collection of Conjectures and Open Questions: Automatic Expansions in Two Bases
Problem 10.32 asks whether some irrational real number has automatic expansions in two multiplicatively independent bases. The answer is no. Adamczewski and Faverjon [AF20] proved it with the multivariate Mahler method, in a form that is stronger than the question asked: the base-$b$ digit sequence may be $k$-automatic for an arbitrary $k \ge 2$, not only for $k = b$.
The definitions used here are in FormalConjecturesForMathlib:
Nat.MultiplicativelyIndependent and Nat.MultiplicativelyIndependentFamily,
AutomaticSequence.IsAutomatic, AutomaticSequence.IsAutomaticInBase and
AutomaticSequence.IsBroadlyAutomaticInBase.
References:
- AF20 Adamczewski, Boris, and Colin Faverjon. "Mahler's method in several variables and finite automata." arXiv:2012.08283 (2020). Appendix A, Conjectures A.2 and A.3, both proved there from Part (i) of Theorem 1.1.
- [AS03] Allouche, Jean-Paul, and Jeffrey Shallit. "Automatic Sequences: Theory, Applications, Generalizations." Cambridge University Press, 2003. Chapter 13, Open Problems 7, p. 403, is the problem that Problem 10.32 modifies.
- [Bug12] Bugeaud, Yann. "Distribution modulo one and Diophantine approximation." Vol. 193. Cambridge University Press, 2012. Chapter 10.
- [Cob69] Cobham, Alan. "On the base-dependence of sets of numbers recognizable by finite automata." Mathematical Systems Theory 3 (1969): 186-192.
- [LvdP82] Loxton, John H., and Alfred J. van der Poorten. "Arithmetic properties of the solutions of a class of functional equations." Journal für die reine und angewandte Mathematik 330 (1982): 159-172. Its transcendence method was the first attack on the problem; Nishioka later reported a gap in its main proof.
Imports (1)
- theorem
Bugeaud32.adamczewski_faverjonAdamczewski–Faverjon [AF20, Conjecture A.3], proved there from Part (i) of Theorem 1.1 sorry line 71 sourceSource documentation
Adamczewski–Faverjon [AF20, Conjecture A.3], proved there from Part (i) of Theorem 1.1. Let $b_1, \dots, b_r$ be multiplicatively independent positive integers, and for every $i$ let $\xi_i$ be a real number that is automatic in base $b_i$. Then $\xi_1, \dots, \xi_r$ are algebraically independent over $\mathbb{Q}$, unless one of them is rational.
Two points of fidelity. The hypothesis is the joint multiplicative independence of $b_1, \dots, b_r$ that [AF20] defines on p. 3 (no nonzero integer tuple $(n_i)$ has $\prod_i b_i^{n_i} = 1$), not the weaker pairwise condition; it is what the proof feeds to Part (i) of Theorem 1.1, via the multiplicative independence of $1/b_1, \dots, 1/b_r$. Automaticity is the broad notion that the proof of Conjecture A.3 uses: the base-$b_i$ digits of $\xi_i$ are $k$-automatic for some $k \ge 2$, which need not be $b_i$.
depends on sorry what this means
Statement uses:
Nat,Fin,LE.le,OfNat.ofNat, Nat.MultiplicativelyIndependentFamily,Real, AutomaticSequence.IsBroadlyAutomaticInBase,Irrational,AlgebraicIndependent,RatProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous28 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem adamczewski_faverjon {r : ℕ} (b : Fin r → ℕ) (hb : ∀ i, 2 ≤ b i) (hind : Nat.MultiplicativelyIndependentFamily b) (ξ : Fin r → ℝ) (hauto : ∀ i, IsBroadlyAutomaticInBase (b i) (ξ i)) (hirr : ∀ i, Irrational (ξ i)) : AlgebraicIndependent ℚ ξ := by …Mentions: Nat.MultiplicativelyIndependentFamily
- theorem
Bugeaud32.problem_10_32.variants.strongProblem 10.32, strong form line 85 sourceSource documentation
Problem 10.32, strong form. No irrational real number is automatic in two multiplicatively independent bases, in the broad sense that its digit sequence in each of the two bases is
k-automatic for somek. This is [AF20, Conjecture A.2], with the broad notion of automaticity that its proof provides.depends on sorry what this means
Statement uses:
Real,Irrational,Nat,LE.le,OfNat.ofNat, Nat.MultiplicativelyIndependent, AutomaticSequence.IsBroadlyAutomaticInBase,FalseProof uses:
AlgebraicIndependent,Fin,Nat.succ,Rat,Matrix.vecCons,Matrix.vecEmpty, Bugeaud32.adamczewski_faverjon,List,List.Mem,Eq,List.finRange,HEq,Membership.mem,Finset,Fintype.elems,Fintype.complete,List.cons,List.Mem.head,Fin.mk,Nat.le_of_ltand 24 more27 instances, coercions and auxiliary constants left out.
Tactic trace: 14 steps
Open to load the checked before-and-after goal states.
theorem problem_10_32.variants.strong (ξ : ℝ) (hξ : Irrational ξ) (b₁ b₂ : ℕ) (hb₁ : 2 ≤ b₁) (hb₂ : 2 ≤ b₂) (hind : Nat.MultiplicativelyIndependent b₁ b₂) (h₁ : IsBroadlyAutomaticInBase b₁ ξ) (h₂ : IsBroadlyAutomaticInBase b₂ ξ) : False := by …Mentions: Nat.MultiplicativelyIndependent
- theorem
Bugeaud32.problem_10_32Problem 10.32 line 103 sourceSource documentation
Problem 10.32. Is there an irrational real number whose expansions in two multiplicatively independent bases can both be generated by a finite automaton? The answer is no, by [AF20].
depends on sorry what this means
Statement uses:
Iff,False,Exists,Real,And,Irrational,Nat,LE.le,OfNat.ofNat, Nat.MultiplicativelyIndependent, AutomaticSequence.IsAutomaticInBaseProof uses:
iff_of_false,not_false, Bugeaud32.problem_10_32.variants.strong, AutomaticSequence.IsAutomaticInBase.broad6 instances, coercions and auxiliary constants left out.
Tactic trace: 3 steps
Open to load the checked before-and-after goal states.
theorem problem_10_32 : answer(False) ↔ ∃ ξ : ℝ, Irrational ξ ∧ ∃ b₁ b₂ : ℕ, 2 ≤ b₁ ∧ 2 ≤ b₂ ∧ Nat.MultiplicativelyIndependent b₁ b₂ ∧ IsAutomaticInBase b₁ ξ ∧ IsAutomaticInBase b₂ ξ := by …Mentions: Nat.MultiplicativelyIndependent