OAI/Probability/InvariantIsing/Haar/HaarDerivative.lean
2 declarations, 0 contain sorry, 0 declared as axioms
Differentiating Haar rotation invariance
Infinitesimal Haar invariance gives the integral identity for spectral Ward identities under explicit domination assumptions.
- abbrev
OAI.InvariantIsing.Orthogonalline 19Also declared: ComparatorChallenges/InvariantIsing.lean:27 (same declaration text).
- lemma
OAI.InvariantIsing.integral_rotation_derivative_eq_zeroline 22Source documentation
A dominated infinitesimal left rotation has Haar mean zero.
lemma integral_rotation_derivative_eq_zero {N : ℕ} (μ : Measure (Orthogonal N)) [μ.IsMulLeftInvariant] (R : ℝ → Orthogonal N) (hR : R 0 = 1) (f : Orthogonal N → ℝ) (hf : Measurable f) (hfi : Integrable f μ) (f' : ℝ → Orthogonal N → ℝ) (hf' : AEStronglyMeasurable (f' 0) μ) (B : Orthogonal N → ℝ) (hB : Integrable B μ) (hbound : ∀ᵐ U ∂μ, ∀ t ∈ Set.Ioo (-1 : ℝ) 1, ‖f' t U‖ ≤ B U) (hderiv : ∀ᵐ U ∂μ, ∀ t ∈ Set.Ioo (-1 : ℝ) 1, HasDerivAt (fun s => f (R s * U)) (f' t U) t) : ∫ U, f' 0 U ∂μ = 0 := by …Mentions: OAI.InvariantIsing.Orthogonal