OAI/Probability/InvariantIsing/Cavity/ConsecutiveBlockSplit.lean
3 declarations, 0 contain sorry, 0 declared as axioms
Removing the last consecutive constrained block gives exactly the base/cavity product constraint.
- def
OAI.InvariantIsing.consecutiveBlockJoinline 14 - lemma
OAI.InvariantIsing.consecutiveBlockJoin_memline 20 - lemma
OAI.InvariantIsing.consecutiveBlockConstraint_succline 49