OAI/Probability/InvariantIsing/Cavity/CavityGaussianTestLaw.lean

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3 declarations, 0 contain sorry, 0 declared as axioms

A bounded Gibbs replica test depends on a centered Gaussian field only through its covariance, including for the countable leaf prior.

  1. theorem OAI.InvariantIsing.cavity_twoReplica_same_covariance line 14
  2. theorem OAI.InvariantIsing.cavity_twoReplica_gaussian_transport line 44

    Source documentation

    Pull back both the energy and the test by a prior-preserving configuration map. This retains the common Gaussian disorder.

    theorem cavity_twoReplica_gaussian_transport {X : Type*} [MeasurableSpace X]
        (ν : Measure X) [IsProbabilityMeasure ν] (e : X → X)
        (he : MeasurePreserving e ν ν) (H : X → ℝ) (hH : Measurable H)
        (C : X → ℕ →₀ ℝ) (hC : ∀ g, Measurable (fun x => cylinderField (C x) g))
        (F : (Fin 2 → X) → ℝ) (hF : Measurable F) :
        (∫ g, referenceReplicaMean ν
          (fun x => H (e x) + cylinderField (C (e x)) g)
          (fun σ => F (fun i => e (σ i))) ∂gaussianCoordinates) =
        ∫ g, referenceReplicaMean ν (fun x => H x + cylinderField (C x) g) F
          ∂gaussianCoordinates := by
    …
  3. theorem OAI.InvariantIsing.cavity_twoReplica_ensemble_symmetry line 60

    Source documentation

    A symmetry of the deterministic energy and Gaussian covariance, combined with invariance of the disorder and the prior, gives the full annealed replica-test symmetry.

    theorem cavity_twoReplica_ensemble_symmetry {Ω X : Type*}
        [MeasurableSpace Ω] [MeasurableSpace X] [Countable X]
        [MeasurableSingletonClass X]
        (μ : Measure Ω) (R : Ω → Ω) (hR : MeasurePreserving R μ μ)
        (ν : Measure X) [IsProbabilityMeasure ν]
        (e : X → X) (he : MeasurePreserving e ν ν)
        (H : Ω → X → ℝ) (C : Ω → X → ℕ →₀ ℝ)
        (M V : Ω → ℝ) (hH : ∀ ω x, |H ω x| ≤ M ω)
        (hV : ∀ ω x, (C ω x).sum (fun _ z => z ^ 2) ≤ V ω)
        (henergy : ∀ ω x, H (R ω) (e x) = H ω x)
        (hcov : ∀ ω x y, cylinderCross (C (R ω) (e x)) (C (R ω) (e y)) =
          cylinderCross (C ω x) (C ω y))
    …