OAI/GroupTheory/PolycyclicRecognition/Analysis/ProbeTileSelector.lean
1 declarations, 0 contain sorry, 0 declared as axioms
Borel selection of the actual finite probe tiles
- theorem
OAI.PolycyclicRecognition.exists_measurable_probe_tile_indexline 14Source documentation
A measurable finite partition gives a measurable tile index on its covered set. Empty tiles and an empty covered set cause no difficulty.
theorem exists_measurable_probe_tile_index {X : Type*} [MeasurableSpace X] {m : ℕ} (U : Set X) (tile : Fin m → Set X) (hm : ∀ j, MeasurableSet (tile j)) (hd : Pairwise (fun j k => Disjoint (tile j) (tile k))) (hcover : (⋃ j, tile j) = U) : ∃ index : U → Fin m, Measurable index ∧ (∀ x, x.val ∈ tile (index x)) ∧ ∀ j, index ⁻¹' {j} = Subtype.val ⁻¹' tile j := by …