OAI/Geometry/EinsteinFour/Moments.lean
3 declarations, 0 contain sorry, 0 declared as axioms
The integer reduction in the balanced-Weyl-moment argument.
Volume is normalized so that the Euler identity is
2 + n + m = volume * (1 + P + Q).
- theorem
OAI.PositiveEinsteinFour.ordered_harmonic_countsline 15Source documentation
The characteristic identities, two gaps, and upper volume estimate leave only the ordered exceptional pair
(n₊, n₋) = (2, 1)if the counts differ.theorem ordered_harmonic_counts (n m : ℕ) (P Q volume : ℝ) (hP : 1 ≤ P) (hQ : 1 ≤ Q) (horder : Q ≤ P) (hsum : P + Q < 4) (hvolume : 0 < volume) (hupper : volume ≤ 2 * (1 - 3 / 40 * (P + Q))) (heuler : 2 + (n : ℝ) + (m : ℝ) = volume * (1 + P + Q)) (hsignature : (n : ℝ) - (m : ℝ) = 2 / 3 * volume * (P - Q)) : n = m ∨ n = 2 ∧ m = 1 := by … - theorem
OAI.PositiveEinsteinFour.exceptional_moment_relationline 51Source documentation
In the exceptional count pair, the larger second moment is fixed by the smaller one. This is the exact
13/7relation used before the two-moment obstruction.theorem exceptional_moment_relation (P Q volume : ℝ) (heuler : 5 = volume * (1 + P + Q)) (hsignature : 1 = 2 / 3 * volume * (P - Q)) : P = (13 * Q + 3) / 7 := by … - theorem
OAI.PositiveEinsteinFour.exceptional_moment_constraintline 65Source documentation
Integrating
v² ≤ (2-b)²with the exceptional relation yields the second constraint of the scalar moment obstruction.meanis the mean ofb.theorem exceptional_moment_constraint (P Q mean : ℝ) (hrelation : P = (13 * Q + 3) / 7) (hpointwise_integral : P ≤ 4 - 4 * mean + Q) : 28 * mean + 6 * Q ≤ 25 := by …