OAI/Combinatorics/Progressions/Linear/SplitSurjectionBasis.lean
3 declarations, 0 contain sorry, 0 declared as axioms
- def
OAI.Erdos3.splitSurjectionEquivline 16 - theorem
OAI.Erdos3.splitSurjectionEquiv_applyline 35 - theorem
OAI.Erdos3.exists_basis_of_surjectionline 39