OAI/Analysis/SeparableQuotients/ProductQuotients.lean
4 declarations, 0 contain sorry, 0 declared as axioms
- lemma
OAI.SeparableQuotient.hasSQ_of_adjoint_not_SSline 21 - lemma
OAI.SeparableQuotient.norm_dual_prod_leline 38 - lemma
OAI.SeparableQuotient.top_infiniteline 58 - theorem
OAI.SeparableQuotient.hasSQ_prod_casesline 66Source documentation
The separable quotient dichotomy for a product, via the evaluation criterion.
theorem hasSQ_prod_cases (h : HasSeparableQuotient 𝕜 (X × Y)) : HasSeparableQuotient 𝕜 X ∨ HasSeparableQuotient 𝕜 Y := by …