OAI/Analysis/OInfinity/ConnectedRowCompletion.lean
3 declarations, 0 contain sorry, 0 declared as axioms
Connected choices of finite binary completions
Three orthogonal buffer isometries let two finite rows with actual unused isometries be matched on the left by a connected unitary. Applying this to the finite shift equations gives a full binary completion with a connected left cocycle relative to a prescribed reference row. Left matching alone is not an assertion of conjugacy.
- lemma
OAI.WeakPureInfiniteness.connectedRow_product_gramline 21 - lemma
OAI.WeakPureInfiniteness.exists_connected_finite_row_leftMatchline 31Source documentation
Only the two displayed commutations with the unused isometries are needed. The buffer need not commute with the tested finite rows.
lemma exists_connected_finite_row_leftMatch [Nontrivial E] {n : ℕ} (x y : Fin n → E) (hx : ∀ i j, star (x i) * x j = if i = j then 1 else 0) (hy : ∀ i j, star (y i) * y j = if i = j then 1 else 0) (e f : E) (he : star e * e = 1) (hf : star f * f = 1) (hxe : ∀ i, star (x i) * e = 0) (hyf : ∀ i, star (y i) * f = 0) (r : Fin 3 → E) (hr : ∀ i j, star (r i) * r j = if i = j then 1 else 0) (her : Commute (star (r 0)) e) (hfr : Commute (star (r 1)) f) : ∃ u : unitary E, Joined (1 : unitary E) u ∧ ∀ i, (u : E) * x i = y i := by … - lemma
OAI.WeakPureInfiniteness.exists_connected_binary_row_completionline 102Source documentation
The tested finite row is the initial binary prefix, and the full binary row has a connected left cocycle to the specified reference.
lemma exists_connected_binary_row_completion [Nontrivial E] {n : ℕ} (x : Fin (n + 1) → E) (hx : ∀ i j, star (x i) * x j = if i = j then 1 else 0) (e : E) (he : star e * e = 1) (hxe : ∀ i, star (x i) * e = 0) (b : Fin 2 → E) (hb : ∀ i j, star (b i) * b j = if i = j then 1 else 0) (hbs : (∑ i, b i * star (b i)) = 1) (r : Fin 3 → E) (hr : ∀ i j, star (r i) * r j = if i = j then 1 else 0) (her : Commute (star (r 0)) e) (hfr : Commute (star (r 1)) (b 0 * e)) : ∃ a : Fin 2 → E, ∃ u : unitary E, Joined (1 : unitary E) u ∧ …