OAI/Analysis/LipschitzHilbert/Trees/SourceCrudeMoment.lean
3 declarations, 0 contain sorry, 0 declared as axioms
The linear node envelope gives the crude normalized moment on the whole phase tube. Only the first power of the mass is integrated; its remaining small power is controlled by the root mass bound.
- theorem
OAI.LipschitzHilbert.source_node_normalized_energy_leline 16 - theorem
OAI.LipschitzHilbert.source_node_normalized_momentline 44 - theorem
OAI.LipschitzHilbert.eventually_source_crude_normalized_momentline 78Source documentation
For p=√L the root mass contributes only exp(4√L), uniformly in the imaginary phase. This is the crude estimate in §11.
theorem eventually_source_crude_normalized_moment (q b : ℝ) (_hb : 0 ≤ b) : ∀ᶠ L : ℝ in atTop, ∀ (μ : Measure X) (n : X → ℝ) (A : X → EuclideanSpace ℂ κ) (U S alpha r : ℝ), (∀ x, 0 < n x) → (∀ x, n x ≤ U) → Measurable n → Integrable n μ → Measurable A → 0 < U → 0 ≤ S → 1 ≤ alpha → alpha ≤ 3 → 0 ≤ r → Real.log U ≤ 2*L → (∫ x, n x ∂μ) ≤ L^b*S → (∀ x, ‖A x‖ ≤ L^q*(1+r)*n x) → Integrable (fun x => ‖(n x^(alpha/Real.sqrt L-1)) • A x‖^(Real.sqrt L)) μ ∧ (∫ x, ‖(n x^(alpha/Real.sqrt L-1)) • A x‖^(Real.sqrt L) ∂μ)^(1/Real.sqrt L) ≤ (L^(q+1)*S^(1/Real.sqrt L))*(1+r)*Real.exp (4*Real.sqrt L) := by …