OAI/Analysis/KadisonKastler/MeasurableConullRepresentations.lean
3 declarations, 0 contain sorry, 0 declared as axioms
Measurable representatives of a separable operator-algebra field
A single measurable conull set suffices for every algebra element and vector. Countably many dense tests are made measurable there; continuity supplies the remaining evaluations without any uncountable intersection of conull sets.
- theorem
OAI.KadisonKastler.measurable_of_dense_parametersline 24 - theorem
OAI.KadisonKastler.exists_conull_measurable_representationsline 45Source documentation
An a.e. measurable representation field is strongly Borel measurable on a single measurable conull subset, simultaneously for all evaluations.
theorem exists_conull_measurable_representations (μ : Measure X) (ρ : X → A →⋆ₙₐ[ℂ] (H →L[ℂ] H)) (hρ : ∀ a v, AEStronglyMeasurable (fun x => ρ x a v) μ) : ∃ s : Set X, MeasurableSet s ∧ μ sᶜ = 0 ∧ ∀ a v, Measurable fun x : s => ρ x.val a v := by … - theorem
OAI.KadisonKastler.exists_measurable_nonunitalRepresentation_versionline 75Source documentation
Extend the common conull restriction by the zero representation. This preserves every fixed algebra element almost everywhere and is Borel everywhere.
theorem exists_measurable_nonunitalRepresentation_version (μ : Measure X) (ρ : X → A →⋆ₙₐ[ℂ] (H →L[ℂ] H)) (hρ : ∀ a v, AEStronglyMeasurable (fun x => ρ x a v) μ) : ∃ σ : X → A →⋆ₙₐ[ℂ] (H →L[ℂ] H), (∀ a v, Measurable fun x => σ x a v) ∧ ∀ a, ∀ᵐ x ∂μ, σ x a = ρ x a := by …