OAI/Algebra/Finitistic/Localization/CompletedShiftedCornerEvaluation.lean
1 declarations, 0 contain sorry, 0 declared as axioms
- theorem
OAI.LittleFinitistic.QuadraticEncoding.completed_shifted_corner_squareline 15Source documentation
The same corner action evaluates correctly on every formal shift, including shift 3.
theorem completed_shifted_corner_square (n : ℤ) : (completedDerivedEvaluation X).map (((functorExtension₂ (BoundedQ P) (BoundedQ P)).obj (shiftFunctor (BoundedQ P) n)).map (quotientCornerEnd e a he)) ≫ (completedShiftedSummandImageIso X e he n).hom = (completedShiftedSummandImageIso X e he n).hom ≫ (evaluatedCornerEnd X e a)⟦n⟧' := by …Mentions: OAI.LittleFinitistic.QuadraticEncoding.completedDerivedEvaluation, OAI.LittleFinitistic.QuadraticEncoding.BoundedQ, OAI.LittleFinitistic.QuadraticEncoding.quotientCornerEnd, OAI.LittleFinitistic.QuadraticEncoding.completedShiftedSummandImageIso, OAI.LittleFinitistic.QuadraticEncoding.evaluatedCornerEnd