OAI/Algebra/DepthFive/MixedOperatorBidegree.lean
9 declarations, 0 contain sorry, 0 declared as axioms
The mixed operator restricts to the finite bidegree spaces used by the rank measure.
- theorem
OAI.Problem335.weight_map_homline 16 - theorem
OAI.Problem335.weighted_homogeneous_mapline 21 - def
OAI.Problem335.bidegreeCastline 28 - def
OAI.Problem335.bidegreeSignline 31 - theorem
OAI.Problem335.bidegreeCast_injectiveline 34 - theorem
OAI.Problem335.operatorWeight_bidegreeline 38 - theorem
OAI.Problem335.mixedOperator_mem_bidegreeSubmoduleline 47Source documentation
Differentiation by a polynomial of bidegree
(k,m)lowers derivative degree bykand raises multiplication degree bym.theorem mixedOperator_mem_bidegreeSubmodule (isV : σ → Bool) {q p : MvPolynomial σ K} {k m a b : ℕ} (hka : k ≤ a) (hq : q ∈ bidegreeSubmodule isV k m) (hp : p ∈ bidegreeSubmodule isV a b) : mixedOperator isV q p ∈ bidegreeSubmodule isV (a - k) (b + m) := by …Mentions: OAI.Problem335.bidegreeSubmodule, OAI.Problem335.mixedOperator
- theorem
OAI.Problem335.mixedOperator_eq_zero_of_bidegree_ltline 63Source documentation
More differentiation than the available derivative degree annihilates the input.
theorem mixedOperator_eq_zero_of_bidegree_lt (isV : σ → Bool) {q p : MvPolynomial σ K} {k m a b : ℕ} (hka : a < k) (hq : q ∈ bidegreeSubmodule isV k m) (hp : p ∈ bidegreeSubmodule isV a b) : mixedOperator isV q p = 0 := by …Mentions: OAI.Problem335.bidegreeSubmodule, OAI.Problem335.mixedOperator
- theorem
OAI.Problem335.mixedOperator_mem_bidegreeSubmodule_allline 83Source documentation
The degree-shift membership also holds without a degree inequality: when
k > a, the output is zero and belongs to every homogeneous submodule.theorem mixedOperator_mem_bidegreeSubmodule_all (isV : σ → Bool) {q p : MvPolynomial σ K} {k m a b : ℕ} (hq : q ∈ bidegreeSubmodule isV k m) (hp : p ∈ bidegreeSubmodule isV a b) : mixedOperator isV q p ∈ bidegreeSubmodule isV (a - k) (b + m) := by …Mentions: OAI.Problem335.bidegreeSubmodule, OAI.Problem335.mixedOperator