FormalConjectures/Wikipedia/conjecture_1_3_to_2_3.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
The $\frac 1 3$–$\frac 2 3$ conjecture
Reference: Wikipedia
Imports (1)
- theorem
Conjecture_1_3_to_2_3.conjecture_1_3_to_2_3Does every finite partially ordered set that is not totally ordered contain two elements sorry line 39 sourceSource documentation
Does every finite partially ordered set that is not totally ordered contain two elements $x$ and $y$ such that the probability that $x$ appears before $y$ in a random linear extension is between $\frac 1 3$ and $\frac 2 3$?
The set of all total order extensions is represented as order preserving bijections $P$ of $1, ..., n$.
depends on sorry what this means
Statement uses:
Iff,True,Finite,PartialOrder,Not,Std.Total,LE.le,Set,OrderHom,Nat,Membership.mem,Eq,Set.range,Set.Icc,OfNat.ofNat,Nat.card,Exists,Rat,HDiv.hDiv,Set.ncardand 3 moreProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous28 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem conjecture_1_3_to_2_3 : answer(sorry) ↔ ∀ (P : Type) [Finite P] [PartialOrder P] (not_total : ¬ Std.Total (α := P) (· ≤ ·)) (total_ext : Set <| OrderHom P ℕ) …