FormalConjectures/Kourovka/8_8.lean
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2 declarations, 2 contain sorry, 0 declared as axioms
Conjecture 8.8
by R. I. Grigorchuk
Both parts of the problem are due to D. V. Anosov.
Reference: The Kourovka Notebook
Imports (1)
- theorem
Kourovka.«8.8».kourovka_8_8aDoes there exist a non-cyclic finitely-generated group $G$ containing an element $a$ such that every element of $G$ is conjugate to a power of $a$? sorry line 44 sourceSource documentation
Does there exist a non-cyclic finitely-generated group $G$ containing an element $a$ such that every element of $G$ is conjugate to a power of $a$?
Here a power of $a$ means $a^n$ for some $n \in \mathbb{Z}$.
Answered affirmatively by V. S. Guba, Math. USSR-Izv. 29 (1986), 233–277.
depends on sorry what this means
Statement uses:
Iff,True,Exists,Group,And,Not,IsCyclic,Group.FG,Int,IsConj,HPow.hPowProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat,Nat11 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem kourovka_8_8a : answer(True) ↔ ∃ (G : Type) (_ : Group G), ¬ IsCyclic G ∧ Group.FG G ∧ ∃ a : G, ∀ g : G, ∃ n : ℤ, IsConj g (a ^ n) := by … - theorem
Kourovka.«8.8».kourovka_8_8bDoes there exist a non-cyclic finitely presented group $G$ which contains an element $a$ such that each element of $G$ is conjugate to some power of $a$? sorry line 56 sourceSource documentation
Does there exist a non-cyclic finitely presented group $G$ which contains an element $a$ such that each element of $G$ is conjugate to some power of $a$?
Here a power of $a$ means $a^n$ for some $n \in \mathbb{Z}$.
depends on sorry what this means
Statement uses:
Iff,True,Exists,Group,And,Not,IsCyclic,Group.IsFinitelyPresented,Int,IsConj,HPow.hPowProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat,Nat11 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem kourovka_8_8b : answer(sorry) ↔ ∃ (G : Type) (_ : Group G), ¬ IsCyclic G ∧ Group.IsFinitelyPresented G ∧ ∃ a : G, ∀ g : G, ∃ n : ℤ, IsConj g (a ^ n) := by …