FormalConjectures/GreensOpenProblems/5.lean
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Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
4 declarations, 4 contain sorry, 0 declared as axioms
Ben Green's Open Problem 5
References:
- [Gr24] Green, Ben. "100 open problems." (2024).
- [BaSo85] Babai L, Sós VT. Sidon sets in groups and induced subgraphs of Cayley graphs. European Journal of Combinatorics. 1985 Jun 1;6(2):101-14.
- [Ke97] Kedlaya, K. S., Large product-free subsets of finite groups, J. Combin. Theory Ser. A 77 (1997), no. 2, 339–343.
- [Ke09] Kedlaya, K. S., Product-free subsets of groups, then and now, Contemp. Math., 479, American Mathematical Society, Providence, RI, 2009, 169–177.
- [Go08] Gowers, W. T., Quasirandom groups, Combin. Probab. Comput. 17 (2008), no. 3, 363–387.
Imports (1)
- theorem
Green5.green_5Which finite groups have the smallest biggest product-free sets? sorry line 54 sourceSource documentation
Which finite groups have the smallest biggest product-free sets?
We formalise this as: determine the supremum of exponents $\alpha$ such that every nontrivial finite group of order $n$ contains a product-free set of size $\geq c n^{\alpha}$ for some absolute constant $c > 0$. (The trivial group is excluded since its only product-free subset is empty.) Kedlaya [Ke97] showed that $\alpha = 11/14$ is admissible, and Green suggests this exponent may well be sharp; the candidate extremal family is the Ree groups ${}^2G_2(q)$, $q = 3^{2m+1}$.
depends on sorry what this means
Statement uses:
IsLUB,Real,Set.ofPred,Exists,And,GT.gt,OfNat.ofNat,Group,Fintype,Nontrivial,Finset, IsProductFree,LE.le,HMul.hMul,HPow.hPow,Fintype.card,Finset.card,sorryAx,Bool.falseProof uses:
Lean.Name,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,Nat35 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_5 : IsLUB {α : ℝ | ∃ c > (0 : ℝ), ∀ (G : Type) [Group G] [Fintype G], Nontrivial G → ∃ S : Finset G, IsProductFree (S : Set G) ∧ c * (Fintype.card G : ℝ) ^ α ≤ (S.card : ℝ)} answer(sorry) := by …Mentions: c, IsProductFree
- theorem
Green5.green_5.variants.kedlayaKedlaya [Ke97] observed, refining some work of Babai and Sós [BaSo85], that it follows from the classification of finite simple groups that every finite group sorry line 67 sourceSource documentation
Kedlaya [Ke97] observed, refining some work of Babai and Sós [BaSo85], that it follows from the classification of finite simple groups that every finite group $G$ of order $n$ has a product-free subset of size $\gg n^{11/14}$.
depends on sorry what this means
Statement uses:
Exists,Real,And,GT.gt,OfNat.ofNat,Group,Fintype,Nontrivial,Finset, IsProductFree,LE.le,HMul.hMul,HPow.hPow,Fintype.card,HDiv.hDiv,Nat,Finset.cardProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous48 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_5.variants.kedlaya : ∃ c > (0 : ℝ), ∀ (G : Type) [Group G] [Fintype G], Nontrivial G → ∃ S : Finset G, IsProductFree (S : Set G) ∧ c * (Fintype.card G : ℝ) ^ ((11 : ℝ) / 14) ≤ (S.card : ℝ) := by …Mentions: c, IsProductFree
- theorem
Green5.green_5.variants.sl_twoA good model problem would be to determine the largest product-free subsets of $\mathrm{SL}_2(\mathbb{F}_p)$ sorry line 80 sourceSource documentation
A good model problem would be to determine the largest product-free subsets of $\mathrm{SL}_2(\mathbb{F}_p)$.
depends on sorry what this means
Statement uses:
Nat,Fact,Nat.Prime,Finset,Matrix.SpecialLinearGroup,Fin,OfNat.ofNat,ZMod,sorryAx,Bool.false,MaximalFor,Set, IsProductFree,Set.ncardProof uses:
Lean.Name,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous16 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_5.variants.sl_two (p : ℕ) [Fact p.Prime] : let S : Finset (SL₂ p) := answer(sorry) … - theorem
Green5.green_5.variants.gowers_sl_twoFor the largest product-free subsets of $\mathrm{SL}_2(\mathbb{F}_p)$ of order $n$, the best-known upper bound is $O(n^{8/9})$, due to Gowers [Go08] sorry line 90 sourceSource documentation
For the largest product-free subsets of $\mathrm{SL}_2(\mathbb{F}_p)$ of order $n$, the best-known upper bound is $O(n^{8/9})$, due to Gowers [Go08].
depends on sorry what this means
Statement uses:
Exists,Real,And,GT.gt,OfNat.ofNat,Nat,Fact,Nat.Prime,Finset,Matrix.SpecialLinearGroup,Fin,ZMod, IsProductFree,LE.le,Finset.card,HMul.hMul,HPow.hPow,Fintype.card,HDiv.hDivProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous68 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_5.variants.gowers_sl_two : ∃ C > (0 : ℝ), ∀ (p : ℕ) [Fact p.Prime], ∀ S : Finset (SL₂ p), IsProductFree (S : Set (SL₂ p)) → (S.card : ℝ) ≤ C * (Fintype.card (SL₂ p) : ℝ) ^ ((8 : ℝ) / 9) := by …Mentions: IsProductFree