FormalConjectures/GreensOpenProblems/49.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Green's Open Problem 49
Also known as the Marton's conjecture or the Polynomial Freiman-Ruzsa conjecture (PFR).
References:
- [Gr24] Ben Green's 100 Open Problems
- [Aa19] Aaronson, James. "A counterexample to a strong variant of the Polynomial Freiman-Ruzsa conjecture." arXiv preprint arXiv:1902.00353 (2019).
- [Fa00] I. Farah, Approximate homomorphisms. II. Group homomorphisms, Combinatorica 20 (2000), no. 1, 47–60.
- [GGM25] W. T. Gowers, B. J. Green, F. Manners and T. C. Tao, On a conjecture of Marton, Ann. of Math. (2) 201 (2025), no. 2, 515–549.
- [Gr05] B. J. Green, Finite field models in additive combinatorics, Surveys in combinatorics 2005, 1–27, London Math. Soc. Lecture Note Ser., 327, Cambridge Univ. Press, Cambridge, 2005.
- [GrTa10] B. J. Green and T. C. Tao An equivalence between inverse sumset theorems and inverse conjectures for the U3 norm, Math. Proc. Cambridge Philos. Soc. 149 (2010), no. 1, 1–19.
- [Lo12] S. Lovett, Equivalence of polynomial conjectures in additive combinatorics, Combinatorica 32 (2012), no. 5, 607–618.
- [LoRe17] S. Lovett and O. Regev, A counterexample to a strong variant of the Polynomial Freiman Ruzsa conjecture in Euclidean space, Discrete Anal.(2017), Paper No. 8, 6 pp.
- [Ma19] F. R. W. M. Manners, Formulations of the PFR conjecture over Z, Math. Proc. Cambridge Philos. Soc. 166 (2019), no. 2, 243–245.
- [Sa12] T. Sanders, On the Bogolyubov-Ruzsa lemma, Anal. PDE 5 (2012), no. 3, 627–655.
- [Ta08] T. C. Tao, A counterexample to a strong polynomial Freiman-Ruzsa conjecture, blog post November 2008, available at http://tinyurl.com/36j6hyxv.
Imports (1)
- theorem
Green49.green_49Suppose that $A \subset \mathbb{F}_2^n$ is a set with $|A + A| \leq K|A|$ sorry line 55 sourceSource documentation
Suppose that $A \subset \mathbb{F}_2^n$ is a set with $|A + A| \leq K|A|$. Is it true that $A$ is covered by $K^{O(1)}$ translates of a subspace of size $\leq |A|$?
Solved by [GGM25], with at most $2K^{12}$ translates. The factor $2$ cannot be omitted: for $A = \mathbb{F}_2^n \setminus \{0\}$ one has $K = 2^n / (2^n - 1)$, so $K^C \to 1$ as $n \to \infty$, while every subspace of size at most $|A|$ is proper and two translates are needed.
depends on sorry what this means
Statement uses:
Iff,True,Exists,Nat,And,GT.gt,OfNat.ofNat,Finset, 𝔽₂,Finset.Nonempty,Real,GE.ge,LE.le,Finset.card,HAdd.hAdd,Fin,ZMod,HMul.hMul,Submodule,Nat.cardand 4 moreProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous80 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_49 : answer(True) ↔ ∃ C > 0, ∀ n (A : Finset (𝔽₂ n)), A.Nonempty → ∀ K ≥ (1 : ℝ), (#(A + A) : ℝ) ≤ K * #A → ∃ (W : Submodule (ZMod 2) (𝔽₂ n)) (T : Finset (𝔽₂ n)), Nat.card W ≤ #A ∧ (#T : ℝ) ≤ 2 * K ^ C ∧ (A : Set (𝔽₂ n)) ⊆ T + W := by …Mentions: 𝔽₂