FormalConjectures/GreensOpenProblems/15.lean
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2 declarations, 2 contain sorry, 0 declared as axioms
Green's Open Problem 15
References:
- [Gr24] Green, Ben. "100 open problems." (2024).
- [BJP14] T. Brown, V. Jungić and A. Poelstra, "On double 3-term arithmetic progressions", Integers 14 (2014), Paper No. A43.
- [CCS14] J. Cassaigne, J. D. Currie, L. Schaeffer and J. Shallit, "Avoidance of additive cubes and related results", Adv. in Appl. Math. 56 (2014), 25–66.
Imports (1)
- theorem
Green15.green_15Does there exist a Lipschitz function $f : \mathbb{N} \to \mathbb{Z}$ whose graph $\Gamma = \{(n, f(n)) : n \in \mathbb{N}\} \subseteq \mathbb{Z}^2$ is free of 3-term progressions? sorry line 43 sourceSource documentation
Does there exist a Lipschitz function $f : \mathbb{N} \to \mathbb{Z}$ whose graph $\Gamma = \{(n, f(n)) : n \in \mathbb{N}\} \subseteq \mathbb{Z}^2$ is free of 3-term progressions?
depends on sorry what this means
Statement uses:
Iff,True,Exists,NNReal,Nat,Int,And,LipschitzWith, Set.IsAPOfLengthFree,Prod,Set.ofPred,Eq,Prod.mk,OfNat.ofNat,ENatProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous26 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_15 : answer(sorry) ↔ ∃ K : ℝ≥0, ∃ f : ℕ → ℤ, LipschitzWith K f ∧ IsAPOfLengthFree {((n, f n) : ℤ × ℤ) | (n : ℕ)} 3 := by … - theorem
Green15.green_15_ap4The answer is YES for 4-term progressions [BJP14] sorry line 52 sourceSource documentation
The answer is YES for 4-term progressions [BJP14].
depends on sorry what this means
Statement uses:
Exists,NNReal,Nat,Int,And,LipschitzWith, Set.IsAPOfLengthFree,Prod,Set.ofPred,Eq,Prod.mk,OfNat.ofNat,ENatProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous26 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem green_15_ap4 : ∃ K : ℝ≥0, ∃ f : ℕ → ℤ, LipschitzWith K f ∧ IsAPOfLengthFree {((n, f n) : ℤ × ℤ) | (n : ℕ)} 4 := by …