FormalConjectures/ErdosProblems/915.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

2 declarations, 2 contain sorry, 0 declared as axioms

Erdős Problem 915

References:

Imports (1)
  1. theorem Erdos915.erdos_915 sorry line 64 source

    depends on sorry what this means

    Statement uses: Iff, False, Nat, LE.le, OfNat.ofNat, Fintype, SimpleGraph, Eq, Fintype.card, HAdd.hAdd, HMul.hMul, HSub.hSub, Set.ncard, Sym2, SimpleGraph.edgeSet, Nat.choose, Exists, And, Ne, Finset and 6 more

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    22 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

  2. theorem Erdos915.erdos_915.variants.edge_disjoint The edge-disjoint reading of erdős_915 sorry line 80 source

    Source documentation

    The edge-disjoint reading of erdős_915. Mader [Ma73] proved that if a graph with $n$ vertices has more than $$\frac{m}{2}(n-1)-\frac{1}{2}(e_0(G)+\cdots+e_{m-2}(G))$$ edges then $G$ contains two vertices connected by $m$ edge-disjoint paths (where $e_r(G)$ counts the number of vertices of degree $\leq r$). In particular, this confirms (and is stronger than) the conjecture.

    L4DEL explanation

    The edge-disjoint reading of erdős_915. Mader [Ma73] proved that if a graph with $n$ vertices has more than $$\frac{m}{2}(n-1)-\frac{1}{2}(e_0(G)+\cdots+e_{m-2}(G))$$ edges then $G$ contains two vertices connected by $m$ edge-disjoint paths (where $e_r(G)$ counts the number of vertices of degree $\leq r$). In particular, this confirms (and is stronger than) the conjecture.

    Sources and attribution: Pinned Lean source (1646ca16afd6)

    depends on sorry what this means

    Statement uses: Iff, True, Nat, LE.le, OfNat.ofNat, Fintype, SimpleGraph, Eq, Fintype.card, HAdd.hAdd, HMul.hMul, HSub.hSub, Set.ncard, Sym2, SimpleGraph.edgeSet, Nat.choose, Exists, And, Ne, Finset and 7 more

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    22 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_915.variants.edge_disjoint : answer(True) ↔
        ∀ m n : ℕ, 2 ≤ m → 1 ≤ n → ∀ (V : Type) [Fintype V] (G : SimpleGraph V),
          Fintype.card V = 1 + n * (m - 1) → G.edgeSet.ncard = 1 + n * m.choose 2 →
            ∃ u v : V, u ≠ v ∧ ∃ P : Finset (G.Walk u v), P.card = m ∧ (∀ p ∈ P, p.IsPath) ∧
              (P : Set (G.Walk u v)).Pairwise fun p q => List.Disjoint p.edges q.edges := by
    …