FormalConjectures/ErdosProblems/914.lean
Explanation legend Lean4 Domain Explanation Language (L4DEL)
L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.
- L4DEL
- Lean4 Domain Explanation Language
Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.
Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
2 declarations, 2 contain sorry, 0 declared as axioms
Erdős Problem 914
References:
- erdosproblems.com/914
- [CoHa63] Corrádi, K. and Hajnal, A., On the maximal number of independent circuits in a graph. Acta Math. Acad. Sci. Hungar. (1963), 423-439.
- [HaSz70] Hajnal, A. and Szemerédi, E., Proof of a conjecture of P. Erdős. (1970), 601-623.
- [KiKo08] Kierstead, H. A. and Kostochka, A. V., A short proof of the Hajnal-Szemerédi theorem on equitable colouring. Combin. Probab. Comput. (2008), 265-270.
Imports (1)
- theorem
Erdos914.erdos_914Let $r\geq 2$ and $m\geq 1$ sorry line 46 sourceSource documentation
Let $r\geq 2$ and $m\geq 1$. Every graph with $rm$ vertices and minimum degree at least $m(r-1)$ contains $m$ vertex disjoint copies of $K_r$.
When $r=2$ this follows from Dirac's theorem. Corrádi and Hajnal [CoHa63] proved this when $r=3$. Hajnal and Szemerédi [HaSz70] proved this for all $r\geq 4$.
A shorter proof was given by Kierstead and Kostochka [KiKo08].
depends on sorry what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,Fintype,SimpleGraph,DecidableRel,SimpleGraph.Adj,Eq,Fintype.card,HMul.hMul,HSub.hSub,SimpleGraph.minDegree,Exists,Fin,Finset,And,SimpleGraph.IsNClique,Pairwise,DisjointProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous16 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_914 {r m : ℕ} (hr : 2 ≤ r) (hm : 1 ≤ m) {V : Type*} [Fintype V] (G : SimpleGraph V) [DecidableRel G.Adj] (hV : Fintype.card V = r * m) (hdeg : m * (r - 1) ≤ G.minDegree) : ∃ K : Fin m → Finset V, (∀ i, G.IsNClique r (K i)) ∧ Pairwise fun i j => Disjoint (K i) (K j) := by … - theorem
Erdos914.erdos_914.variants.equitable_colouringDocumented declaration: equitable_colouring sorry line 59 sourceSource documentation
Equivalently, every graph with $rm$ vertices and maximum degree at most $m-1$ has a proper vertex colouring with $m$ colours in which every colour class has exactly $r$ vertices (an equitable colouring).
depends on sorry what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,Fintype,SimpleGraph,DecidableRel,SimpleGraph.Adj,Eq,Fintype.card,HMul.hMul,SimpleGraph.maxDegree,HSub.hSub,Exists,SimpleGraph.Coloring,Fin,Set.ncard,SimpleGraph.Coloring.colorClassProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous12 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_914.variants.equitable_colouring {r m : ℕ} (hr : 2 ≤ r) (hm : 1 ≤ m) {V : Type*} [Fintype V] (G : SimpleGraph V) [DecidableRel G.Adj] (hV : Fintype.card V = r * m) (hdeg : G.maxDegree ≤ m - 1) : ∃ C : G.Coloring (Fin m), ∀ i, (C.colorClass i).ncard = r := by …