FormalConjectures/ErdosProblems/780.lean
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Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
2 declarations, 2 contain sorry, 0 declared as axioms
Erdős Problem 780
References:
- erdosproblems.com/780
- [Er76] Erdős, Paul, Problems and results in combinatorial analysis. Colloquio Internazionale sulle Teorie Combinatorie (Roma, 1973), Tomo II (1976), 3-17.
- [Lo78] Lovász, L., Kneser's conjecture, chromatic number, and homotopy. J. Combin. Theory Ser. A (1978), 319-324.
- [AFL86] Alon, N. and Frankl, P. and Lovász, L., The chromatic number of Kneser hypergraphs. Trans. Amer. Math. Soc. (1986), 359-370.
Imports (1)
- theorem
Erdos780.erdos_780sorry line 47 sourcedepends on sorry what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,HAdd.hAdd,HMul.hMul,HSub.hSub,Subtype,Finset,Fin,Eq,Finset.card,Exists,And,Pairwise,DisjointProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous22 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
- theorem
Erdos780.erdos_780.variants.sharpDocumented declaration: sharp sorry line 60 sourceSource documentation
This would be best possible: if $n=kr-1+(t-1)(k-1)$ then decomposing $[n]$ as one set $X_1$ of size $kr-1$ and $t-1$ sets $X_2,\ldots,X_{t}$ of size $k-1$, a colouring without $k$ pairwise disjoint edges is given colouring all subsets of $X_1$ in colour $1$ and assigning an edge with colour $2\leq i\leq t$ if $i$ is minimal such that $X_i$ intersects the edge.
depends on sorry what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,Exists,Subtype,Finset,Fin,HAdd.hAdd,HSub.hSub,HMul.hMul,Eq,Finset.card,Not,And,Pairwise,DisjointProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous22 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_780.variants.sharp (k r t : ℕ) (hk : 1 ≤ k) (hr : 1 ≤ r) (ht : 1 ≤ t) : ∃ c : {e : Finset (Fin (k * r - 1 + (t - 1) * (k - 1))) // e.card = r} → Fin t, ¬ ∃ (i : Fin t) (e : Fin k → {e : Finset (Fin (k * r - 1 + (t - 1) * (k - 1))) // e.card = r}), (∀ j, c (e j) = i) ∧ Pairwise fun a b ↦ Disjoint (e a).1 (e b).1 := by …Mentions: c