FormalConjectures/ErdosProblems/727.lean
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4 declarations, 4 contain sorry, 0 declared as axioms
Erdős Problem 727
Reference: erdosproblems.com/727
Imports (1)
- theorem
Erdos727.erdos_727Let $k ≥ 2$ sorry line 36 sourceSource documentation
Let $k ≥ 2$. Does $((n+k)!)^2∣(2n)!$ hold for infinitely many $n$?
depends on sorry what this means
Statement uses:
Iff,True,Nat,GE.ge,OfNat.ofNat,Set.Infinite,Set.ofPred,Dvd.dvd,HPow.hPow,Nat.factorial,HAdd.hAdd,HMul.hMulProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous22 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_727 : answer(sorry) ↔ ∀ k ≥ 2, Set.Infinite {n : ℕ | (Nat.factorial (n + k)) ^ 2 ∣ Nat.factorial (2 * n)} := by … - theorem
Erdos727.erdos_727.variants.k_2It is open even for $k = 2$ sorry line 45 sourceSource documentation
It is open even for $k = 2$. Let $k = 2$. Does $((n+k)!)^2∣(2n)!$ hold for infinitely many n?
depends on sorry what this means
Statement uses:
Iff,True,Set.Infinite,Nat,Set.ofPred,Dvd.dvd,HPow.hPow,Nat.factorial,HAdd.hAdd,OfNat.ofNat,HMul.hMulProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous20 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_727.variants.k_2 : letI k := 2 … - theorem
Erdos727.erdos_727.variants.k_1Balakran proved this holds for $k = 1$ sorry line 56 sourceSource documentation
Balakran proved this holds for $k = 1$.
Let $k = 1$. Does $((n+k)!)^2∣(2n)!$ for infinitely many $n$?
depends on sorry what this means
Statement uses:
Iff,True,Set.Infinite,Nat,Set.ofPred,Dvd.dvd,HPow.hPow,Nat.factorial,HAdd.hAdd,OfNat.ofNat,HMul.hMulProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous20 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_727.variants.k_1 : letI k := 1 … - theorem
Erdos727.erdos_727.variants.k_1_2Erdős, Graham, Ruzsa, and Straus observe that the method of Balakran can be further used to prove that there are infinitely many $n$ such that $(n+k)!(n+1)!∣(2n)!$ sorry line 66 sourceSource documentation
Erdős, Graham, Ruzsa, and Straus observe that the method of Balakran can be further used to prove that there are infinitely many $n$ such that $(n+k)!(n+1)!∣(2n)!$
depends on sorry what this means
Statement uses:
Nat,LE.le,OfNat.ofNat,Set.Infinite,Set.ofPred,Dvd.dvd,HMul.hMul,Nat.factorial,HAdd.hAddProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous14 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_727.variants.k_1_2 (k : ℕ) (hk : 2 ≤ k) : Set.Infinite {n : ℕ | (Nat.factorial (n + k)) * (Nat.factorial (n + 1)) ∣ Nat.factorial (2 * n)} := by …