FormalConjectures/ErdosProblems/623.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 623
Reference: erdosproblems.com/623
Imports (1)
- theorem
Erdos623.erdos_623Let $X$ be a set of cardinality $\aleph_\omega$ and $f$ be a function from the finite subsets of $X$ to $X$ such that $f(A)\not\in A$ for all $A$ sorry line 39 sourceSource documentation
Let $X$ be a set of cardinality $\aleph_\omega$ and $f$ be a function from the finite subsets of $X$ to $X$ such that $f(A)\not\in A$ for all $A$. Must there exist an infinite $Y\subseteq X$ that is independent - that is, for all finite $B\subset Y$ we have $f(B)\not\in Y$?
depends on sorry what this means
Statement uses:
Iff,True,Eq,Cardinal,Cardinal.mk,OrderEmbedding,Ordinal,Cardinal.aleph,Ordinal.omega0,Finset,Not,Membership.mem,Exists,Set,And,Set.Infinite,LE.leProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous,OfNat.ofNat,Nat23 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_623 : answer(sorry) ↔ ∀ (X : Type u) (hX : #X = ℵ_ ω) (f : Finset X → X), (∀ A : Finset X, f A ∉ A) → (∃ Y : Set X, Set.Infinite Y ∧ (∀ (B : Finset X), ↑B ⊆ Y → f B ∉ Y)) := by …