FormalConjectures/ErdosProblems/537.lean
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- Lean4 Domain Explanation Language
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Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1
1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 537
References:
- erdosproblems.com/537
- [Er73] Erdős, P., Problems and results on combinatorial number theory. A survey of combinatorial theory (Proc. Internat. Sympos., Colorado State Univ., Fort Collins, Colo., 1971) (1973), 117-138.
Imports (1)
- theorem
Erdos537.erdos_537Let $\epsilon>0$ and $N$ be sufficiently large sorry line 52 sourceSource documentation
Let $\epsilon>0$ and $N$ be sufficiently large. If $A\subseteq \{1,\ldots,N\}$ has $\lvert A\rvert \geq \epsilon N$ then must there exist $a_1,a_2,a_3\in A$ and distinct primes $p_1,p_2,p_3$ such that $$a_1p_1=a_2p_2=a_3p_3?$$
A positive answer would imply [536].
Erdős describes a construction of Ruzsa which disproves this: consider the set of all squarefree numbers of the shape $p_1\cdots p_r$ where $p_{i+1}>2p_i$ for $1\leq i<r$. This set has positive density, and hence if $A$ is its intersection with $(N/2,N)$ then $\lvert A\rvert \gg N$ for all large $N$. Suppose now that $p_1a_1=p_2a_2=p_3a_3$ where $a_i\in A$ and $p_1,p_2,p_3$ are distinct primes. Without loss of generality we may assume that $a_2>a_3$ and hence $p_2<p_3$, and so since $p_2p_3\mid a_1\in A$ we must have $2<p_3/p_2$. On the other hand $p_3/p_2=a_2/a_3\in (1,2)$, a contradiction.
L4DEL explanation
Let $\epsilon>0$ and $N$ be sufficiently large. If $A\subseteq \{1,\ldots,N\}$ has $\lvert A\rvert \geq \epsilon N$ then must there exist $a_1,a_2,a_3\in A$ and distinct primes $p_1,p_2,p_3$ such that $$a_1p_1=a_2p_2=a_3p_3?$$ A positive answer would imply [536]. Erdős describes a construction of Ruzsa which disproves this: consider the set of all squarefree numbers of the shape $p_1\cdots p_r$ where $p_{i+1}>2p_i$ for $1\leq ia_3$ and hence $p_2<p_3$, and so since $p_2p_3\mid a_1\in A$ we must have $2<p_3/p_2$. On the other hand $p_3/p_2=a_2/a_3\in (1,2)$, a contradiction.
Sources and attribution: Pinned Lean source (1646ca16afd6)
depends on sorry what this means
Statement uses:
Iff,False,Real,LT.lt,OfNat.ofNat,Filter.Eventually,Nat,Finset,LE.le,Finset.Icc,GE.ge,Finset.card,HMul.hMul,Exists,And,Membership.mem,Nat.Prime,Ne,Eq,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous34 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_537 : answer(False) ↔ ∀ ε : ℝ, 0 < ε → ∀ᶠ N : ℕ in atTop, ∀ A ⊆ Finset.Icc 1 N, (A.card : ℝ) ≥ ε * N → ∃ a₁ ∈ A, ∃ a₂ ∈ A, ∃ a₃ ∈ A, ∃ p₁ p₂ p₃ : ℕ, p₁.Prime ∧ p₂.Prime ∧ p₃.Prime ∧ p₁ ≠ p₂ ∧ p₁ ≠ p₃ ∧ p₂ ≠ p₃ ∧ a₁ * p₁ = a₂ * p₂ ∧ a₂ * p₂ = a₃ * p₃ := by …