FormalConjectures/ErdosProblems/498.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 498
References:
- erdosproblems.com/498
- [Er61] Erdős, Paul, Some unsolved problems. Magyar Tud. Akad. Mat. Kutató Int. Közl. (1961), 221-254.
- [Er45] Erdős, P., On a lemma of Littlewood and Offord. Bull. Amer. Math. Soc. (1945), 898-902.
- [Kl65] Kleitman, Daniel J., On a lemma of Littlewood and Offord on the distribution of certain sums. Math. Z. (1965), 251-259.
- [Kl70] Kleitman, Daniel J., On a lemma of Littlewood and Offord on the distributions of linear combinations of vectors. Advances in Math. (1970), 155-157.
Imports (1)
- theorem
Erdos498.erdos_498Let $z_1,\ldots,z_n\in\mathbb{C}$ with $1\leq \lvert z_i\rvert$ for $1\leq i\leq n$ sorry line 53 sourceSource documentation
Let $z_1,\ldots,z_n\in\mathbb{C}$ with $1\leq \lvert z_i\rvert$ for $1\leq i\leq n$. Let $D$ be an arbitrary disc of radius $1$. Is it true that the number of sums of the shape $$\sum_{i=1}^n\epsilon_iz_i \textrm{ for }\epsilon_i\in \{-1,1\}$$ which lie in $D$ is at most $\binom{n}{\lfloor n/2\rfloor}$?
A strong form of the Littlewood-Offord problem. Erdős [Er45] proved this is true if $z_i\in\mathbb{R}$, and for general $z_i\in\mathbb{C}$ proved a weaker upper bound of $$\ll \frac{2^n}{\sqrt{n}}.$$ This was solved in the affirmative by Kleitman [Kl65], who also later generalised this to arbitrary Hilbert spaces [Kl70].
See also [395].
depends on sorry what this means
Statement uses:
Iff,True,Nat,Fin,Complex,LE.le,Real,OfNat.ofNat,Norm.norm,Set.ncard,Int,Set.ofPred,And,Or,Eq,Neg.neg,Membership.mem,Set,Metric.ball,Finset.sumand 4 moreProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous44 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_498 : answer(True) ↔ ∀ (n : ℕ) (z : Fin n → ℂ), (∀ i, 1 ≤ ‖z i‖) → ∀ c : ℂ, {ε : Fin n → ℤ | (∀ i, ε i = -1 ∨ ε i = 1) ∧ (∑ i, (ε i : ℂ) * z i) ∈ Metric.ball c 1}.ncard ≤ n.choose (n / 2) := by …Mentions: c