FormalConjectures/ErdosProblems/386.lean
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3 declarations, 3 contain sorry, 0 declared as axioms
Erdős Problem 386
Reference: erdosproblems.com/386
Imports (1)
- theorem
Erdos386.erdos_386Let $2 \le k \le n - 2$ sorry line 38 sourceSource documentation
Let $2 \le k \le n - 2$. Can $\binom{n}{k}$ be the product of consecutive primes infinitely often? Here $k$ may vary with $n$: the question asks for infinitely many admissible binomial coefficients, not for a single $k$ that works infinitely often.
depends on sorry what this means
Statement uses:
Iff,True,Filter.Frequently,Nat,Exists,And,GE.ge,OfNat.ofNat,LE.le,HSub.hSub,Eq,Nat.choose,Finset.prod,Finset.Ico,Nat.nth,Nat.Prime,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous14 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_386 : answer(sorry) ↔ ∃ᶠ n in .atTop, ∃ k ≥ 2, k ≤ n - 2 ∧ ∃ p q : ℕ, n.choose k = ∏ i ∈ .Ico p q, nth Nat.Prime i := by … - theorem
Erdos386.erdos_386.variants.forallFor all $2 \le k \le n - 2$, can $\binom{n}{k}$ be the product of consecutive primes infinitely often? sorry line 48 sourceSource documentation
For all $2 \le k \le n - 2$, can $\binom{n}{k}$ be the product of consecutive primes infinitely often?
depends on sorry what this means
Statement uses:
Iff,True,Nat,GE.ge,OfNat.ofNat,Filter.Frequently,And,LE.le,HSub.hSub,Exists,Eq,Nat.choose,Finset.prod,Finset.Ico,Nat.nth,Nat.Prime,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous14 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_386.variants.forall : answer(sorry) ↔ ∀ k ≥ 2, ∃ᶠ n in .atTop, k ≤ n - 2 ∧ ∃ p q : ℕ, n.choose k = ∏ i ∈ .Ico p q, nth Nat.Prime i := by … - theorem
Erdos386.erdos_386.variants.twoCan $\binom{n}{2}$ be the product of consecutive primes infinitely often? sorry line 57 sourceSource documentation
Can $\binom{n}{2}$ be the product of consecutive primes infinitely often?
depends on sorry what this means
Statement uses:
Iff,True,Filter.Frequently,Nat,And,LE.le,OfNat.ofNat,HSub.hSub,Exists,Eq,Nat.choose,Finset.prod,Finset.Ico,Nat.nth,Nat.Prime,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous14 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_386.variants.two : answer(sorry) ↔ ∃ᶠ n in .atTop, 2 ≤ n - 2 ∧ ∃ p q : ℕ, n.choose 2 = ∏ i ∈ .Ico p q, nth Nat.Prime i := by …