FormalConjectures/ErdosProblems/384.lean

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Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

2 declarations, 2 contain sorry, 0 declared as axioms

Erdős Problem 384

References:

Imports (1)
  1. theorem Erdos384.erdos_384 If $1k^2$ the binomial coefficient $\binom{n}{k}$ is divisible by a prime $p<n/k$ sorry line 52 source

    Source documentation

    If $1<k<n-1$ then $\binom{n}{k}$ is divisible by a prime $p\leq n/2$ (except $\binom{7}{3}=\binom{7}{4}=5\cdot 7$).

    A conjecture of Erdős and Selfridge [ErGr80]. Proved by Ecklund [Ec69], who made the stronger conjecture that whenever $n>k^2$ the binomial coefficient $\binom{n}{k}$ is divisible by a prime $p<n/k$. Discussed in problem B31 and B33 of Guy's collection [Gu04]. Stronger forms of this conjecture are 1094 and 1095.

    Ecklund's theorem is stated for $n \geq 2k$ with the single exception $\binom{7}{3}$; by the symmetry $\binom{n}{k} = \binom{n}{n-k}$ this is the form above, where $\binom{7}{4}$ is the second exception. The prime bound is $p \leq n/2$ (that is, $2p \leq n$); see erdos_384.variants.strict for the strict inequality.

    L4DEL explanation

    If $1k^2$ the binomial coefficient $\binom{n}{k}$ is divisible by a prime $p<n/k$. Discussed in problem B31 and B33 of Guy's collection [Gu04]. Stronger forms of this conjecture are 1094 and 1095. Ecklund's theorem is stated for $n \geq 2k$ with the single exception $\binom{7}{3}$; by the symmetry $\binom{n}{k} = \binom{n}{n-k}$ this is the form above, where $\binom{7}{4}$ is the second exception. The prime bound is $p \leq n/2$ (that is, $2p \leq n$); see erdos_384.variants.strict for the strict inequality.

    Sources and attribution: Pinned Lean source (1646ca16afd6)

    depends on sorry what this means

    Statement uses: Nat, LT.lt, OfNat.ofNat, HSub.hSub, Ne, Prod, Prod.mk, Exists, And, Nat.Prime, Dvd.dvd, Nat.choose, LE.le, HMul.hMul

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    16 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_384 (n k : ℕ) (hk : 1 < k) (hkn : k < n - 1) (h₃ : (n, k) ≠ (7, 3))
        (h₄ : (n, k) ≠ (7, 4)) :
        ∃ p : ℕ, p.Prime ∧ p ∣ n.choose k ∧ 2 * p ≤ n := by
    …
  2. theorem Erdos384.erdos_384.variants.strict sorry line 63 source

    depends on sorry what this means

    Statement uses: Iff, False, Nat, LT.lt, OfNat.ofNat, HSub.hSub, Ne, Prod, Prod.mk, Exists, And, Nat.Prime, Dvd.dvd, Nat.choose, HMul.hMul

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    14 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.