FormalConjectures/ErdosProblems/355.lean

GitHub source file

Explanation legend Lean4 Domain Explanation Language (L4DEL)

L4DEL explanations are a separate layer. They do not change the Lean source. Intuition is explanatory prose; numbered items are a reading path; sources link the wording back to evidence.

L4DEL
Lean4 Domain Explanation Language

Credit: The upstream authors and contributors retain credit for the project and mathematics. lean4-explainer only renders their pinned source and adds the separately disclosed explanation layer.

Project sources: Pinned project documentation, Formal Conjectures paper, arXiv v1

1 declarations, 1 contain sorry, 0 declared as axioms

Erdős Problem 355

References:

Imports (1)
  1. theorem Erdos355.erdos_355 Is there a lacunary sequence sorry line 48 source

    Source documentation

    Is there a lacunary sequence $A\subseteq \mathbb{N}$ (so that $A=\{a_1 < \cdots\}$ and there exists some $\lambda > 1$ such that $a_{n+1}/a_n\geq \lambda$ for all $n\geq 1$) such that $$\left\{ \sum_{a\in A'}\frac{1}{a} : A'\subseteq A\textrm{ finite}\right\}$$ contain all rationals in some open interval?

    Bleicher and Erdős conjectured the answer is no.

    In fact the answer is yes, with any lacunarity constant $\lambda\in (1,2)$ (though not $\lambda=2$), as proved by van Doorn and Kova\v{c} [DoKo25].

    This was formalized in Lean by van Doorn using Aristotle.

    depends on sorry what this means

    Statement uses: Iff, True, Exists, Nat, And, IsLacunary, Real, LT.lt, Rat, Membership.mem, Set, Set.Ioo, Set.ofPred, Finset, LE.le, Set.range, Eq, Finset.sum, HDiv.hDiv, OfNat.ofNat

    Proof uses: sorryAx, Lean.Name, Bool.false, Lean.Name.num, Lean.Name.str, Lean.Name.anonymous

    29 instances, coercions and auxiliary constants left out.

    Tactic trace: 1 steps

    Open to load the checked before-and-after goal states.

    theorem erdos_355 :
        answer(True) ↔ ∃ A : ℕ → ℕ, IsLacunary A ∧ ∃ u v : ℝ, u < v ∧ ∀ q : ℚ, ↑q ∈ Set.Ioo u v →
          q ∈ {∑ a ∈ A', (1 / a : ℚ) | (A' : Finset ℕ) (_ : ↑A' ⊆ Set.range A)} := by
    …

    Mentions: IsLacunary