FormalConjectures/ErdosProblems/243.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 243
Reference: erdosproblems.com/243
Imports (1)
- theorem
Erdos243.erdos_243Let $a_1 < a_2 < \dots$ be a sequence of integers such that $\lim_{n\to\infty} \frac{a_n}{a_{n-1}^2} = 1$ and $\sum \frac{1}{a_n} \in \mathbb{Q}$ sorry line 41 sourceSource documentation
Let $a_1 < a_2 < \dots$ be a sequence of integers such that $\lim_{n\to\infty} \frac{a_n}{a_{n-1}^2} = 1$ and $\sum \frac{1}{a_n} \in \mathbb{Q}$.
Then, for all sufficiently large $n \ge 1$, $a_n = a_{n-1}^2 - a_{n-1} + 1$.
depends on sorry what this means
Statement uses:
Nat,StrictMono,Filter.Tendsto,Real,HDiv.hDiv,HPow.hPow,HSub.hSub,OfNat.ofNat,Filter.atTop,nhds,Summable,Rat,SummationFilter.unconditional,Filter.Eventually,Eq,HAdd.hAddProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous60 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_243 (a : ℕ → ℕ) (ha₀ : StrictMono a) (ha₁ : Tendsto (fun n ↦ (a n : ℝ) / a (n - 1) ^ 2) atTop (𝓝 1)) (ha₂ : Summable ((1 : ℚ) / a ·)) : ∀ᶠ n in atTop, a n = a (n - 1) ^ 2 - a (n - 1) + 1 := by …