FormalConjectures/ErdosProblems/204.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 204
References:
- erdosproblems.com/204
- [Ad25] S. Adenwalla, A Question of Erdős and Graham on Covering Systems. arXiv:2501.15170 (2025).
Imports (1)
- theorem
Erdos204.erdos_204Are there $n$ such that there is a covering system with moduli the divisors of $n$ which is 'as disjoint as possible'? sorry line 47 sourceSource documentation
Are there $n$ such that there is a covering system with moduli the divisors of $n$ which is 'as disjoint as possible'?
That is, for all $d\mid n$ with $d>1$ there is an associated $a_d$ such that every integer is congruent to some $a_d\pmod{d}$, and if there is some integer $x$ with $$x\equiv a_d\pmod{d}\textrm{ and }x\equiv a_{d'}\pmod{d'}$$then $(d,d')=1$.
The density of such $n$ is zero. Erdős and Graham believed that no such $n$ exist.
Adenwalla [Ad25] has proved there are no such $n$.
This was formalized by van Doorn in Lean using Aristotle.
depends on sorry what this means
Statement uses:
Iff,False,Exists,Nat,Int,Set,Set.ofPred,And,Dvd.dvd,GT.gt,OfNat.ofNat,Membership.mem,Int.ModEq,Ne,Eq,Nat.gcdProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous12 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_204 : answer(False) ↔ ∃ (n : ℕ) (a : ℕ → ℤ), let D := {d : ℕ | d ∣ n ∧ d > 1} …