FormalConjectures/ErdosProblems/1219.lean
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2 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 1219
References:
- erdosproblems.com/1219
- [ErHa71] Erdős, Paul and Hajnal, András, Unsolved problems in set theory. Axiomatic Set Theory, Proc. Sympos. Pure Math. XIII Part I (1971), 17-48.
- [Ko25b] Komjáth, Péter, The Erdős–Hajnal problem list. Bull. Symb. Log. (2025), 418-461.
- [Sh75] Shelah, Saharon, Notes on partition calculus. Infinite and finite sets (Colloq., Keszthely, 1973), Colloq. Math. Soc. János Bolyai 10, North-Holland (1975), 1257-1276.
Imports (1)
- theorem
Erdos1219.erdos_1219sorry line 53 sourcedepends on sorry what this means
Statement uses:
Iff,True,Nat,StrictMono,Cardinal,HPow.hPow,OfNat.ofNat,OrderEmbedding,Ordinal,Cardinal.aleph,LT.lt,Ordinal.omega0, Combinatorics.cardinalPartitionRel,Cardinal.sum,Ordinal.ToTypeProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous38 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
- theorem
Erdos1219.erdos_1219.test.aleph_omega_lt_sumUnder the hypotheses oferdos_1219, the target $\aleph_\omega$ is smaller than the source $\sum_k 2^{\aleph_{n_k}}$, so the partition relation is not ruled out by cardinality line 65 sourceSource documentation
Under the hypotheses of
erdos_1219, the target $\aleph_\omega$ is smaller than the source $\sum_k 2^{\aleph_{n_k}}$, so the partition relation is not ruled out by cardinality.standard axioms: Classical.choice, Quot.sound, propext what this means
Statement uses:
Nat,LT.lt,Cardinal,OrderEmbedding,Ordinal,Cardinal.aleph,Ordinal.omega0,HPow.hPow,OfNat.ofNat,Cardinal.sumProof uses:
LT.lt.trans_le,Cardinal.le_sum36 instances, coercions and auxiliary constants left out.
theorem erdos_1219.test.aleph_omega_lt_sum (n : ℕ → ℕ) (h0 : ℵ_ ω < (2 : Cardinal.{u}) ^ ℵ_ (n 0)) : ℵ_ ω < sum fun k => (2 : Cardinal.{u}) ^ ℵ_ (n k) := …