FormalConjectures/ErdosProblems/1029.lean
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1 declarations, 1 contain sorry, 0 declared as axioms
Erdős Problem 1029
References:
- erdosproblems.com/1029
- [Er93] Erdős, Paul, Some of my favorite solved and unsolved problems in graph theory. Quaestiones Math. (1993), 333-350.
- [ErSz35] Erdős, P. and Szekeres, G., A combinatorial problem in geometry. Compos. Math. (1935), 463-470.
- [Sp75] Spencer, J., Ramsey's theorem - a new lower bound. J. Combin. Theory Ser. A (1975), 108-115.
Imports (1)
- theorem
Erdos1029.erdos_1029Documented declaration: erdos_1029 sorry line 48 sourceSource documentation
If $R(k)$ is the Ramsey number for $K_k$, the minimal $n$ such that every $2$-colouring of the edges of $K_n$ contains a monochromatic copy of $K_k$, then $$\frac{R(k)}{k2^{k/2}}\to \infty.$$
In [Er93] Erdős offers $100 for a proof of this and $1000 for a disproof, but says 'this last offer is to some extent phoney: I am sure that this is true (but I have been wrong before).'
depends on sorry what this means
Statement uses:
Filter.Tendsto,Nat,Real,HDiv.hDiv, SimpleGraph.diagonalRamsey,HMul.hMul,HPow.hPow,OfNat.ofNat,Filter.atTopProof uses:
sorryAx,Lean.Name,Bool.false,Lean.Name.num,Lean.Name.str,Lean.Name.anonymous30 instances, coercions and auxiliary constants left out.
Tactic trace: 1 steps
Open to load the checked before-and-after goal states.
theorem erdos_1029 : Tendsto (fun k : ℕ ↦ (SimpleGraph.diagonalRamsey k : ℝ) / ((k : ℝ) * (2 : ℝ) ^ ((k : ℝ) / 2))) atTop atTop := by …Mentions: SimpleGraph.diagonalRamsey