FLT/Mathlib/Topology/MetricSpace/Pseudo/Matrix.lean

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L4DEL
Lean4 Domain Explanation Language

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1 declarations, 0 contain sorry, 0 declared as axioms

Matrix

Material destined for Mathlib.

Imports (3)
Imported by 2 files
  1. theorem DenseRange.exists_matrix_det_ne_zero Let A : X → Matrix n n R be a parameterisation of a matrix ring with entries in a seminormed commutative ring R by a metric space X and let f : Y → X be dense line 24 source

    Source documentation

    Let A : X → Matrix n n R be a parameterisation of a matrix ring with entries in a seminormed commutative ring R by a metric space X and let f : Y → X be dense. If the identity matrix is in the parameterisation A, then there exists a y : Y such that A (f y) has non-zero determinant.

    standard axioms: Classical.choice, Quot.sound, propext what this means

    Statement uses: PseudoMetricSpace, Fintype, DecidableEq, SeminormedCommRing, NormOneClass, IsTopologicalRing, Matrix, Continuous, DenseRange, Eq, OfNat.ofNat, Exists, Ne, Matrix.det

    Proof uses: Set.range, Membership.mem, Set, Function.comp, Set.codRestrict, DenseRange.codRestrict_comp, Continuous.matrix_det, LT.lt, Real, Dist.dist, Subtype.mk, Eq.substr, Exists.intro, rfl, HDiv.hDiv, Nat, Eq.mp, Eq.trans, GT.gt, forall_congr and 86 more

    131 instances, coercions and auxiliary constants left out.

    Tactic trace: 7 steps

    Open to load the checked before-and-after goal states.

    theorem DenseRange.exists_matrix_det_ne_zero {X Y n R : Type*} [PseudoMetricSpace X]
        [Fintype n] [DecidableEq n] [SeminormedCommRing R] [NormOneClass R]
        [IsTopologicalRing R] {A : X → Matrix n n R} {f : Y → X} (hA : Continuous A) (hf : DenseRange f)
        {b : X} (hb : A b = 1) :
        ∃ y, (A (f y)).det ≠ 0 := by
    …